rootbeer003:
help
satellite73:
the five in the denominator is the root, the three in the numerator is the exponent, so \[\sqrt[5]{4^3}\]
rootbeer003:
a?
satellite73:
yes
satellite73:
first off \(\frac{6}{4}\) reduces to \(\frac{3}{2}\) which one is \[\large 3^{\frac{3}{2}}\]
rootbeer003:
b
satellite73:
stupid question the exponent should be \(\frac{3}{8}\)
rootbeer003:
a
satellite73:
3 goes in to 9 3 times, the index should be 3
rootbeer003:
b?
satellite73:
no we can do better \[16=2^4\] so \[\sqrt[3]{16}=\sqrt[3]{2^3\times 2}=\sqrt[3]{2^3}\times \sqrt[3]{2}=2\sqrt[3]{2}\]
rootbeer003:
c lol
satellite73:
repeat?
rootbeer003:
OOPS
satellite73:
no, not D cancel the threes, you get A
rootbeer003:
or b
satellite73:
what is\(\frac{1}{3}+\frac{1}{6}\)?
satellite73:
...
rootbeer003:
a
rootbeer003:
got yogurt
satellite73:
what kind?
satellite73:
it is if you put enough m and m's in it
satellite73:
any guesses for this one?
rootbeer003:
nope
satellite73:
\[8\times \frac{1}{4}=?\]
rootbeer003:
2
rootbeer003:
b
satellite73:
pick the one with \(m^2\) in the numerator
satellite73:
yea B
satellite73:
\[1-\frac{3}{4}=?\]
rootbeer003:
0.25
satellite73:
try \(\frac{1}{4}\) calculator head
rootbeer003:
ouch
satellite73:
then \[\sqrt[4]{16}=?\]
rootbeer003:
2
satellite73:
yes
satellite73:
yes
satellite73:
not sure how you got it, but it is right
rootbeer003:
scuse me
satellite73:
whatever you did, keep it up
satellite73:
last one, since \(3\times 2^x>0\)
satellite73:
\[y=4\]for the same reason as the last one
satellite73:
this has nothing to do with the specific function compared to \[y=f(x)\] the graph of \[y=f(x+4)-2\] is shifted LEFT 4, down 2
satellite73:
too hard for me
rootbeer003:
but u can do anything
rootbeer003:
but geometry
satellite73:
ok fine it is B since if you replace x by 1 you get -4 and if you replace x by 0 you get -7
rootbeer003:
b?
satellite73:
back to easy ones, make a guess
satellite73:
no, the 3 is the power, the 2 is the root \[\sqrt{5^3}\]
rootbeer003:
soooo c
satellite73:
no, \(5^3=125\)
rootbeer003:
sry im retarded
satellite73:
repeat
satellite73:
we don't say retarded anymore, we say "differently abled"
rootbeer003:
lol
rootbeer003:
its not a repeat are you differently abled
satellite73:
\[2\sqrt[3]{2}\]
satellite73:
both right, new thread
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