Question

A flare was launched straight up from the ground with an initial velocity of 176 ft/s and returned to the ground after 11 s.

The height of the flare t seconds after launch is modeled by the function f(t)=−16t^2+176t .

What is the maximum height of the flare, in feet?

Answer 1

@tigerlover

Answer 2

One way to figure out the maximum height is to take the derivative of the equation.
So, f'(t)=-32t+176
Find for what values of t f'(t) is 0, as that is the maximum/minimum of your function (when the slope of the tangent is 0).
So 0=-32t+176
-32t=-176
t=5.5 s.
So at 5.5 s is when a max height takes place. Plug it back into your original equation, and you should get:
f(5.5)=-16(5.5)^2+176(5.5)
f(5.5)=484 ft

Answer 3

Ahhhh

Answer 4

WHo dat?