Question

Solve for x.

Use the quadratic formula.

3x^2+7x+3=0

Enter the solutions, in simplified radical form, in the boxes.

Answer 1

use the quadratic formula \[\large\rm \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
where
a is the leading coefficient
b is the coefficient of middle term
c =constant \[Ax^2+Bx+C=0\]

Answer 2

do i turn 2.70325740 into 2.703 or 2.7?

Answer 3

all of them are not in radical form

Answer 4

how do I put them in radical form?

Answer 5

plugin the a ,b ,c values into the formula and then simplify it that will give you radical form answer.

Answer 6

So a=2 b=1 and c=3?

Answer 7

@Nnesha

Answer 8

c is correct.
a is the leading coefficient not the exponent \[Ax^2\]
the number infront of the `x^2` variable will be a

Answer 9

so for your equation A=3 and b=7
\[\color{Red}{3}x^2+\color{blue}{7}x+\color{orange}{3}=0\]
\[\color{Red}{A}x^2+\color{blue}{B}x+\color{orange}{C}=0\]

Answer 10

so -7+- 49-36 over 8?

Answer 11

yes that's correct. don't forget the denominator
2(a)=2(3)

Answer 12

isnt 2^3= to 8?

Answer 13

oh wait its 2*3 lol 6

Answer 14

\[\frac{ -7 \pm \sqrt{13 }}{ 6 }\]

Answer 15

yes right and since it's plus minus we can separate tem \[\frac{ -7-\sqrt{13} }{ 6 } , \frac{-7+\sqrt{13}}{6}\]

Answer 16

thats simplified radical form?

Answer 17

that's it.

Answer 18

thank you :D

Answer 19

yw