an equilibrium mixture consists of 0.25 M NO2 (g) and 0.45 M N2O4 (g) in a 0.75 L container. A chemist wishes to add some NO2 (g) to this mixture in order to increase the equilibrium amount of NO2 to 0.50 moles. assume the temperature and volume are constant. How many moles of NO2 (g) must be added to the container?
@Ultrilliam
He asked dis on PA~
Whats your point? That doesn't mean it doesn't need to be solved.
Damn it, I thought I'd slide by LOL.
@JustSaiyan
I'll look over it when I get a chance I think it just needs some stoich, no need of using ideal gas law
true
Sorry, I didn't get a chance to look over it till now. The chemist wants to add another 0.25 mols to increase the equilibrium amt of Nitrogen Dioxide to 0.5 mols. So +0.25 mols NO2 * 46grams/1 mol NO2 = 11.5 g NO2 so your answer is 11.5 g NO2. I had a feeling it involves the gas law, but I guess not. I don't know, though, what a question from 2 years ago is doing up here.
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