A small auditorium has 10 rows of seats. There are 12 seats in the first row and 16 seats in the second row. The number of seats in a row continues to increase by 4 with each additional row. What is the total number of seats in the auditorium? 352 156 300 252
@Hero
@Ultrilliam can probably answer this question
I'm busy ATM dealing with ASO and their poor decisions
@rootbeer003, how many questions do you have in total?
3
You have three more questions left?
including this one yes
Okay so this is what you do. We know there are ten rows of seats so we "count" 1st row --- 12 seats 2nd row --- 16 seats 3rd row --- 20 seats ... nth row --- a_n seats So we have to figure out a relationship between n and a_n. We do this by starting with the first row and counting in the following manner: 1st row --- 12 + 0(4) seats 2nd row --- 12 + 1(4) seats 3rd row --- 12 + 2(4) seats ... nth row --- 12 + (n -1)(4) seats
We use this pattern to figure out the number of seats in the 10th row.
10th row ---> 12 + (10 - 1)(4) seats So @rootbeer003 how many seats are there in the 10th row?
48
Very good. Now we have to figure out the total number of seats in the auditorium. Do you have the sum formula with you?
no
\(\sum_{\text{n = 1}}^{10} 12 + (n-1)(4)\)
Ugh, latex is terrible with sums
idk how to use that formula..
@Ultrilliam you should fix this. LaTeX doesn't work well with Sum formulas at all
is it 300?
Are you guessing or did you actually use a formula to come up with that?
The other way to figure it out is to use the following formula: \(\text{Sum} = n\left(\dfrac{a_1 + a_n}{2}\right)\)
What do i put in as a and n
In this case, \(n = 10, a_1 = 12, a_n = 48\), \(\text{Sum} = n\left(\dfrac{a_1 + a_n}{2}\right)\)
In other words n represents total number of rows \(a_1\) represents the first term in the sequence \(a_n\) represents the last term in the sequence
The answer is 300, but you did not explain how you came up with it.
Post as a separate question please.
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