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Mathematics 13 Online
rootbeer003:

help

rootbeer003:

1 attachment
rootbeer003:

@Hero

Hero:

Do you want to learn how to do it?

rootbeer003:

yes

Hero:

With an example...

rootbeer003:

No its fine

Hero:

@rootbeer003 what do you mean "no its fine"?

rootbeer003:

@Hero I mean, i don't need an example. But i would love for you to work through it with me.

Hero:

So you are given |dw:1497561194551:dw| and expected to find the quotient. Polynomial long division works similar to regular long division.

Hero:

First you ask yourself, how many times can \(3x\) be multiplied to get \(9x^2\)? Then answer is \(3x\) times since \(3x \times 3x = 9x^2\). Place the \(3x\) above the \(9x^2\) as shown: |dw:1497561437866:dw|

Hero:

Next, multiply \((3x + 2) \times 3x\). Place the result of that multiplication below \(9x^2 - 9x\) \((3x + 2) \text{ times } 3x \text{ is } 9x^2 + 6x\) as shown: |dw:1497561587967:dw|

Hero:

Next, subtract \(9x^2 + 6x\) from \(9x^2 - 9x\) to get \(-15x\)|dw:1497562158888:dw|

Hero:

Place the -15x directly under the bar below -6x |dw:1497562186724:dw|

Hero:

Then bring down the -10: |dw:1497562276484:dw|

Hero:

Next, ask yourself what can we multiply by 3x to get -15x? In other words \(3x \times \text{___} = -15x\) The answer to that is -5. Place -5 above the 2nd term in the trinomial: |dw:1497562392149:dw|

rootbeer003:

b

rootbeer003:

Thanks for your hard work

Hero:

Now multiply \((3x +2) \times -5\) to get \(-15x - 10\). Place that result directly beneath the one above it:|dw:1497562483098:dw|

Hero:

The remainder is 0

rootbeer003:

New thread?

Hero:

Yes

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