help
@Hero
Do you want to learn how to do it?
yes
With an example...
No its fine
@rootbeer003 what do you mean "no its fine"?
@Hero I mean, i don't need an example. But i would love for you to work through it with me.
So you are given |dw:1497561194551:dw| and expected to find the quotient. Polynomial long division works similar to regular long division.
First you ask yourself, how many times can \(3x\) be multiplied to get \(9x^2\)? Then answer is \(3x\) times since \(3x \times 3x = 9x^2\). Place the \(3x\) above the \(9x^2\) as shown: |dw:1497561437866:dw|
Next, multiply \((3x + 2) \times 3x\). Place the result of that multiplication below \(9x^2 - 9x\) \((3x + 2) \text{ times } 3x \text{ is } 9x^2 + 6x\) as shown: |dw:1497561587967:dw|
Next, subtract \(9x^2 + 6x\) from \(9x^2 - 9x\) to get \(-15x\)|dw:1497562158888:dw|
Place the -15x directly under the bar below -6x |dw:1497562186724:dw|
Then bring down the -10: |dw:1497562276484:dw|
Next, ask yourself what can we multiply by 3x to get -15x? In other words \(3x \times \text{___} = -15x\) The answer to that is -5. Place -5 above the 2nd term in the trinomial: |dw:1497562392149:dw|
b
Thanks for your hard work
Now multiply \((3x +2) \times -5\) to get \(-15x - 10\). Place that result directly beneath the one above it:|dw:1497562483098:dw|
The remainder is 0
New thread?
Yes
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