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@Dumbgirl2 do you remember how to set this one up? The steps are very similar to the last question I helped you with.
Yes, I have the steps written down. My only problem was whenever I put in -16=-4a-2b 18=16a+4b I got the equation 2=12a+2b, and when you divide, it then becomes 0=6a+b+c. My question is, is it possible for it to be like that?
So, when you are responding you should post in this case two things, the original system you came up with and then the last step you left off on. It seems to me you posted the last step you left off on but did not post the original system you started with. Would you mind posting the original system you began with please?
So I should post all the steps I have down so far?
More like the first step and the last step. The first step being the system of three equations you came up with.
The first step you started with (the system of three equations) And the last step you left off on.
1) 16=4a+2b+c 2) 18=16a+4b+c 3) 46=100a+10b+c -16=-4a-2b 18=16a+4b
2=12a+2b---> 2/2=12a/2+2b/2---> 0=6a+b -16=-4a-2b 48=100a+10b
32=96a+8b--->32/8=96a/8+8b/8---> 4=12a+b 0=6a---> 0=-6a 4=12a-->4=12a
4=6a ---> 4/6=0.6-> 0.6=a 0=6(0.6)+b--> 0=3.6+b--> 0-3.6=-3.6-> -3.6=b
That's what I have so far
So here's the original system I have set up: 1) 16=4a+2b+c 2) 18=16a+4b+c 3) `48`=100a+10b+c I highlighted 48 because you put 46 instead of 48. Nevertheless if you subtract the 1st equation from the 2nd, you get 2 = 12a + 2b If you subtract the 2nd equation from the third you get 30 = 14a + b So far we have reduced the original system system to what I call a composite system: 2 = 12a + 2b 30 = 84a + 6b Now if we take the top composite equation and divide both sides of that by 2 we get 1 = 6a + b If we divide both sides of the bottom composite equation by 6, we get 5 = 14a + b And now we are left with a prime system: 1 = 6a + b 5 = 14a + b So, we can subtract the top prime equation from the bottom prime equation to get 4 = 8a Divide both sides by 8 and we have 1/2 = a You should be able to find the values of b and c from here.
Oh, my bad. Guess I'm just tired and in a rush to get it done, thank you
Let me know what values you get for b and c.
I got -2 for b
And 18 for c
Perfect-a-mundo
Thank you
So, the way to know that you are correct is, take one of the original equations and plug in those values like so: 16=4a+2b+c 16 = 4(1/2) + 2(-2) + 18 16 = 2 - 4 + 18 16 = 18 + 2 - 4 16 = 20 - 4 16 = 16
If you do this checking process and you don't end up with both sides equal, then you should go back and check your systems and the values you came with for a,b, and c.
That's what I kept accidentally doing the other times
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