Question

Find the value of each variable. (picture below) WILL MEDAL A. a = 15, b = 5, c = 8, d = 4 B. a = 15, b = 4, c = 8, d = 5 C. a = 14.5, b = 5, c = 6, d = 4 D. a = 14.5, b = 4, c = 6, d = 5

Answer 1

Hi @kodakanderson,
"(picture below)"... Where's the picture?

Answer 2

thx i i didnt know

Answer 3

here the picture

Answer 4

@Ultrilliam

Answer 5

Give me a few to look over this

Answer 6

ight you

Answer 7

here

Answer 8

Okay, so my question to you is, Have you already attempted to solve this yourself?. If so, what have you done so far? You can either explain here or you can use the draw feature to show the work that you've done so far.

Answer 9

Yes, I understand the problem itself, but I'm asking you if you have attempted to solve this on your own yet.

Answer 10

i cant solve it thats why i need help

Answer 11

@kodakanderson
Are you familiar with the concept of similar triangles?

Answer 12

no i m trash at math

Answer 13

Well, the concept of similar triangles is as follows:

If two angles of a triangle have measures equal to the measures of two angles of another triangle, then the triangles are similar. Corresponding sides of similar polygons are in proportion, and corresponding angles of similar polygons have the same measure.

In this case we have three triangles:

Answer 14

Triangle G:

Answer 15

thanks you

Answer 16

Triangle B:

Answer 17

And Triangle R

Answer 18

thanks you

Answer 19

So, in this case, \(\triangle{B} \sim \triangle{R} \sim \triangle{G}\) because their angles all have the same measure:

Answer 20

And thus the corresponding sides of the triangles are proportional

Answer 21

you good at this 😭😎🙂😁😁☺☺☺☺☺☺☺

Answer 22

thatsks too you

Answer 23

For example, we can set up the following proportion to find the length of side b:
\(\dfrac{b}{10} = \dfrac{12.5}{15 + 10}\)

Answer 24

@kodakanderson would you like to try solving for \(b\) for the proportion above?

Answer 25

no

Answer 26

@kodakanderson

Answer 27

Bruh. You need to help yourself for others to help you. ._.