Parabola and its vertex

Question

Dumbgirl2 · Answer

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EvL · Answer

Vertex is given: (h,k) = (-3,-18)
Y-int is (0,0)

From this given info, you can make an equation of the parabola in vertex form: 
$\sf (y-k)=a(x-h)^2$
$\sf (y-(-18))=a(x-(-3)^2$
$\sf (y+18)=a(x+3)^2$

Now, solve for a using the given point (the y-int)
$\sf (y+18)=a(x+3)^2$
$\sf (0+18)=a(0+3)^2$
$\sf (18=3a$
$\sf a=6 $

So your equation will be like this:
$\sf (y+18)=6(x+3)^2$

You are looking for the x-intercepts, this means that y values should be zero. It will be like this $\sf (x_1,0), (x_2,0)$. So substitute y=0 to the equation we came up with ^-^

Ultrilliam · Answer

@dumbgirl2 Your question has been answered, come online to see it ^-^

Dumbgirl2 · Answer

Thank you, I havent been on because I was doing more of the math

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