Question

Parabola and its vertex

Answer 1

Vertex is given: (h,k) = (-3,-18)
Y-int is (0,0)

From this given info, you can make an equation of the parabola in vertex form:
\(\sf (y-k)=a(x-h)^2\)
\(\sf (y-(-18))=a(x-(-3)^2\)
\(\sf (y+18)=a(x+3)^2\)

Now, solve for a using the given point (the y-int)
\(\sf (y+18)=a(x+3)^2\)
\(\sf (0+18)=a(0+3)^2\)
\(\sf (18=3a\)
\(\sf a=6 \)

So your equation will be like this:
\(\sf (y+18)=6(x+3)^2\)

You are looking for the x-intercepts, this means that y values should be zero. It will be like this \(\sf (x_1,0), (x_2,0)\). So substitute y=0 to the equation we came up with ^-^

Answer 2

@dumbgirl2 Your question has been answered, come online to see it ^-^

Answer 3

Thank you, I havent been on because I was doing more of the math