Question

Hey, could anyone teach me how to do this?

Answer 1

@dskumar25 @ThisGirlPretty

Answer 2

Vertex is given: (h,k) = (6,-5)
Y-int is (0,175)

From this given info, you can make an equation of the parabola in vertex form:
\(\sf (y-k)=a(x-h)^2\)
\(\sf (y-(-5))=a(x-6)^2\)
\(\sf (y+5)=a(x-6)^2\)

Now, solve for a using the given point (the y-int)
\(\sf (y+5)=a(x-6)^2\)
\(\sf (175+5)=a(0-6)^2\)
\(\sf (180=36a\)
\(\sf a=5 \)

So your equation will be like this:
\(\sf (y+5)=5(x-6)^2\)

You are looking for the x-intercepts, this means that y values should be zero. It will be like this \(\sf (x_1,0), (x_2,0)\). So substitute y=0 to the equation we came up with ^-^

Answer 3

@BeautifulAngel your question was answered, come on and take a look ^-^