Identify the 10th term for the sequence: 12,6,3,1.5...?
@trish what can we divide 12 by to get 6?
@Hero 0.5
Actually you divide 12 by 2 to get 6.
You can multiply by 0.5 to get 6 as well.
From my perspective, dividing by 2 is easier than multiplying by decimals.
@Hero when I do that both ways I'm getting a long decimal answer and I'm pretty sure it's not the answer
But I understand why you did it. Neverthless it should be obvious how to get to the tenth term.
Okay, so let's do it one step at a time.
I'll show you how it is easy. You just have to be comfortable converting between fraction and decimal.
So let's start with 1.5 Remember, to read 1.5 you say one AND five tenths which we can re-write in fraction form as \(1 + \dfrac{5}{10}\) but reduces to \(1 + \dfrac{1}{2}\)
Now suppose you take \(1 + \dfrac{1}{2}\) and multiply that by \(\dfrac{1}{2}\). If you do that you get \(\dfrac{1}{2} + \dfrac{1}{4}\) which adds to \(\dfrac{3}{4}\) or \(0.75\) in decimal.
Now that's our fifth term. Since we have \(\dfrac{3}{4}\) and need to get the sixth term, all we have to do is multiply \(\dfrac{3}{4}\) by \(\dfrac{1}{2}\) again to get the next term
@Hero as a fraction I got 3/128
Taking another angle at this, \(1.5\) is \(\dfrac{3}{2}\) in fraction form. You can multiply that by \(\dfrac{1}{2}\) to easily get \(\dfrac{3}{4}\)
Since \(\dfrac{3}{2} \times \dfrac{1}{2} = \dfrac{3}{4}\)
@Hero yes I understand the process but I'm hesitant that my answer is incorrect
Okay, so the pattern is \(a_{n-1} \times \dfrac{1}{2} = a_n\) Let: \(a_1 = 12\) \(a_2 = 6\) \(a_3 = 3\) \(a_4 = \dfrac{3}{2}\)
Then \(\begin{align*}a_5 &= a_4 \times \dfrac{1}{2} \\&= \dfrac{3}{2} \times \dfrac{1}{2} \\&= \dfrac{3}{4} \end{align*}\)
So \(a_5 = \dfrac{3}{4}\)
To get \(a_6\) do the same thing.
\(a_6 = a_5 \times \dfrac{1}{2}\)
\(a_6 = \dfrac{3}{4} \times \dfrac{1}{2}\)
@Hero thanks so much I understand it now
Yeah but you never stated the tenth term.
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