Are the following lines parallel, perpendicular, or neither? 3x + 5y = 40 11 - y = 3/5x
@trish, ask yourself the following question: Are the slopes of both lines the same or are they negative reciprocals of one another?
@hero yes they are
@hero oh so it's perpendicular
@trish, Why do you think they are perpendicular?
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@hero it's not sending me an email
@hero I thought they were perpendicular because of the slope being flipped first its 3,5. Then in the next line it has 3/5
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@hero ok I verified it so about the question am I right
Okay so here are the two lines: 3x + 5y = 40 11 - y = (3/5)x Be sure to use parentheses so that people do not interpret \(\dfrac{3}{5}x\) to mean \(\dfrac{3}{5x}\).
@Hero so it is perpendicular?
So the thing is if you multiply both sides of the 2nd equation by 5 you end up with 55 - 5y = 3x Then adding 5y to both sides you get 3x + 5y = 55 which shows that the lines both have the same slope.
are they parallel?
What are your thoughts regarding this? Do you understand what I did?
@hero no
So the 2nd equation gave you was \(11 - y = \dfrac{3}{5}x\) correct?
@trish
yes @hero
Okay so what happens if you try multiplying both sides by 5?
that cancels out and it leaves you with 55-5y=3x
@Hero
Yes correct. And then as I said, when you add 5y to both sides, you end up with 3x + 5y = 55. Compare that with 3x + 5y = 40.
@hero so that means it's neither
@hero I'll try
:D
@Hero oh ok they're parallel
@hero thanks for your help
Yes, parallel correct.
@trish
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