see screenshot below
Ah good old trigonometry. I'm sure you're familiar with the Unit Circle? It's this thing right here.
Before we examine this in detail, I'd like to review the meaning behind sin, cos, and tan, with the device "SOH CAH TOA". In a right triangle, sin is calculated by the length Opposite the angle/the length of the Hypotenuse; cos by the length Adjacent to the angle/the length of the Hypotenuse; tan by the length Opposite the angle/the length Adjacent to the angle
Now, we can relate this to the right triangles that appear in the Unit Circle. Using cos(330) as an example, we see that the corresponding coordinates (sqr(3)/2, -1/2) can be used as the Adjacent and Opposite lengths, respectively. This being the Unit Circle, the Hypotenuse is 1. So, cos in this case would be (sqr(3)/2)/1 or simply sqr(3)/2
this is all good but it's just double angle/half angle formulas
I just googled this and Froppy is correct. Her's is a simpler solution.
if tan(157.5) = tan(x) then x = 315 then tan(157.5) = [1 - cos(315) ]/sin(315) = choice c
you can do something similar with sin(165)
sin(x/2) = +- sqrt(1-cos(2x)/2))
for the last one cos(2x) = 1 - sin^2(x)
then we use process of elimination to find sin^2(157.5)
hope this helps
going to bed
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