Question

Determine whether the vectors u and v are parallel, orthogonal, or neither.

u = <9, 3>, v = <36, 12>

Parallel
Orthogonal
Neither

can someone check my work ? i think the answer is neither because it doesn't equal to zero and they aren't equal when you multiply it. is this correct?

Answer 1

@theDeviliscoming

Answer 2

I'm so sorry but I am horrible at math maybe @Hero can help

Answer 3

I'm about to go for a run. I probably should not have come here. It is not difficult to find videos or websites that show how to solve problems like these.

Answer 4

@Nnesha Can you quickly check this for me?

Answer 5

what isn't equal to zero ??

Answer 6

for it to be orthogonal u ▪ v = 0

Answer 7

yes right

Answer 8

in this problem u ▪ v = 360 so i think its neither because u = 324 , v = 36

Answer 9

did you find the angle between them ?

Answer 10

ok

Answer 11

no , i didn't think i needed to do that because parallel means they're the same correct?

Answer 12

If the angle between them is zero or 180 then it will be parallel

Answer 13

okay so then its the LAST one?

Answer 14

\(\color{#0cbb34}{\text{Originally Posted by}}\) @word2
no , i didn't think i needed to do that because parallel means they're the same correct?
\(\color{#0cbb34}{\text{End of Quote}}\)
yes but what exactly should be the same ?
\[\large\rm u \cdot v \color{reD}{= }\sqrt{u} \sqrt{v}\]
if the above equation is true then it will be parallel

Answer 15

108?

Answer 16

hmm what is the magnitude of u and v ?

Answer 17

\[\sqrt{324}\sqrt{36} = 108\]

Answer 18

the x-component of vector v is 36 so the magnitude should be bigger than that

Answer 19

\[\sqrt{9^2+ 36^2}= 37.01\]

Answer 20

\

Answer 21

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha
\
\(\color{#0cbb34}{\text{End of Quote}}\)
\[\large\rm u=<\color{Red}{9},\color{blue}{3}> ~~~\rightarrow \left| u \right|= \sqrt{\color{reD}{9^2}+\color{blue}{3^2} }\]
https://prnt.sc/g422dq

Answer 22

the component of vector v are 36 and 12 ( not 36 and 9 ) :=))

Answer 23

i did that , 9 * 36 = 324 , 3 *12 = 36

Answer 24

thanks eveyone , i;m going to close this . i go it

Answer 25

\(\color{#0cbb34}{\text{Originally Posted by}}\) @word2
in this problem u ▪ v = 360 so i think its neither because u = 324 , v = 36
\(\color{#0cbb34}{\text{End of Quote}}\)
dot product is 360 but we cannot separate them like u =324 , v=36
\

Answer 26

\[ \large\rm u \cdot v = 324+36\] **

Answer 27

\[\large\rm u=<\color{Red}{9},\color{blue}{3}> ~~~\rightarrow \left| u \right|= \sqrt{\color{reD}{9^2}+\color{blue}{3^2} }\]
\[\large\rm v=<\color{Red}{36},\color{blue}{12}> ~~~\rightarrow \left| v \right|= \sqrt{\color{reD}{(36)^2}+\color{blue}{(12)^2} }\]
\[\large\rm u \cdot v = \left| u \right|\left| v \right|\]

Answer 28

are you talking to me ?

Answer 29

hmm

Answer 30

\(\color{#0cbb34}{\text{Originally Posted by}}\) @sillybilly123
\(\mathbf u = <9,3>\)


\(\mathbf v = <36,12> = 4 <9,3>\)

scalar linearity :)
\(\color{#0cbb34}{\text{End of Quote}}\)
agree w/ ya

Answer 31

cool o^_^o

Answer 32

o^_^o