Simplify 3 with a small 2 in the corner multiplied by 3 with a 5 in the corner 3 with a 7 in the corner 3 with a 10 in the corner 9 with a 7 in the corner 9 with a 10 in the corner
@Ultrilliam
@Vocaloid
when you have numbers with exponents multiplied together, add the exponents
A^M * A^N = A^(M+N) following this pattern: 3^2 * 3^5 = ?
still cant get it : o
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follow the pattern
@SmokeyBrown can you explain this I'm exhausted
can you please just tell me the answer?
@SmokeyBrown
So when you have a number with a number in the corner, the corner number is called an exponent. That means that the number is multiplied by itself that many times. So, 3 with a 7 in the corner is 3*3*3*3*3*3*3, or 3 multiplied by itself 7 times and 3 with a 10 in the corner is 3*3*3*3*3*3*3*3*3*3, or 3 multiplied by itself 10 times
If you multiply these two numbers together, you would get (3 multiplied by itself 7 times) times (3 multiplied by itself 10 times)
thank the lord!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I just became a fan of you!
Another way to state this would be 3 multiplied by itself (10+7) or 17 times. So your final answer would be 3 to the power of 17, 3^17, or 3 with a 17 in the corner. The same rules apply with 9 to the power of 7 times 9 to the power of 10, or any other sets of the same number to the power of something.
You can also apply this rule to division. If, say you were to divide 3^10 by 3^7, your final answer would be 3^(10-7), or 3^3.
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