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Find the limit algebraically as x approaches zero of the function (-6 + x) / x^4 .
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Start by plugging in \(x = 0\) and you will see that this amounts to \(\dfrac{-6}{0}\) Dunno how much formalism you require, but then you can break it out as follows: \(\lim\limits_{x \to 0} \dfrac{-6 + x}{x^4} = \dfrac{\lim\limits_{x \to 0} -6 + x}{\lim\limits_{x \to 0} x^4} = \dfrac{ -6 }{\lim\limits_{x \to 0} x^4}\) Checking for **two-sidedness**, as otherwise you do not have a limit as such, note the denominator is always +ve. That should do it.
@sweetburger you can't do that (the second part)
I realize my mistake. Sorry about that. Not trying to lead anyone the wrong way.
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