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How many complex roots does the equation below have? x ^6 + x ^3 + 1 = 0 The number of complex roots is
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@Zowie @Layla @Vocaloid I need assistance!
6 complex roots
omg you type fast o:
sorry about the weird wacky numbers
lol
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could you explain :L please
Okay so..... hold on
|dw:1505925869877:dw|
ooooooooo ty
then let x^3=u then let x^6= u^2
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The discrimenant is...|dw:1505925993772:dw|
which is negative so, u has two complex roots
So there are two complex values x3. There are 3 complex cube roots of each of those two complex roots for u. Therefore, there are 6 complex roots.
so, that is your answer
tysm for the explanation
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I get it now
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