Warriorz13:
The half-life of 232Th is 1.4x 10^10 years. If there are 25.0 g or the sample left after 2.8 x 10^10 years, how many grams were in the original sample?
Warriorz13:
@JustSaiyan
Warriorz13:
@ThisGirlPretty Just look lol
ThisGirlPretty:
Jesus o.o What kind of teacher would torture such a soul
Warriorz13:
The nicest teacher I got
ThisGirlPretty:
XD I bet, I wish voca was me teacher :I Id understand things better and make better grades :O
Vocaloid:
|dw:1506031628276:dw|
Warriorz13:
Aaaand... confused...
Vocaloid:
A = final amount = 25.0g A_0 = initial amount (what you are solving for) h = half life = 1.4x 10^10 t = time = 2.8 x 10^10 years plug in these values and solve for A0
JustSaiyan:
2.8 ⋅ 10^10 ÷ 1.4 ⋅ 10^10 = 2 25 ÷ (1/2) = 50 ÷ (1/2) = 100g There were 100 grams in the original samle.
JustSaiyan:
Sample*
Vocaloid:
@Warriorz13 do you understand how that calculation was done?
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