Statistics is not my strong point. How do you do this one:- The marks obtained by the class in a test are normally distributed with mean 74 and standard deviation 15. The top 10% get an A grade. Calculate the minimum mark required to get A grade.
I guess you need to use the standardised score equation z = (X - 74) / 15 but how do you get the z score?
z would be 0.1 because it's 10% but you have to change it to a decimal. When changing a percent to a decimal you move the . over 2 places to the right.
But that gives an answer of X = 75.5 but the correct answer is 94.
we have to use the Normal Distribution tables I guess...
Maybe I should be looking at the area under the Normal Cheeseulative curve of > 0.9???
What???? The computer isnt printing what Im typing!!!
It is. I just have no clue what you are talking about. Wouldn't want to give you a bad/wrong answer.
Yes thats fine. I meant to type C u m u l a t i ve.
Solve \(\displaystyle\Phi^{-1}(.90)=\frac{x-74}{15}\) for \(x\) where \(\displaystyle\Phi^{-1}(\cdot)\) is the inverse standard normal CDF.
Ah right Than you.
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