Question

mathalon

Answer 1

l'Hôpital still exists !!

Answer 2

\(\lim\limits_{x \to 0} \dfrac{xe^{6x}-3 \sin x +2x}{2 \cos x-x^2-2}\)

\(\lim\limits_{x \to 0} \dfrac{6xe^{6x}+e^{6x}-3 \cos x +2}{-2 \sin x-2x}\)
hospitality again
\(\lim\limits_{x \to 0} \dfrac{ 6(e^{6x}+ 6xe^{6x})+6e^{6x}+3 \sin x }{-2 \cos x-2}=-3\)

Answer 3

why am i doing algebra stuff
~back to circuits/capacitors stuff.....~

Answer 4

wanna help ??._.??

Answer 5

hmm...geez

Answer 6

Good night sir
have a nice dream!

Answer 7

good night ma'am?

Answer 8

okay sorry
Correction
Good night ma'am :)
have a nice dream!

Answer 9

how so?

Answer 10

what do you mean?🤔

Answer 11

i don't remember deleting any comment
sooo hm what happened to mai first comment

Answer 12

https://prnt.sc/gsj9vg .....

Answer 13

mea fucκin' culpa