Question

Electric Field/Potential Question

Answer 1

@nnesha

Answer 2

so I know that E = -dV/ds and F = qE but I am still not getting the correct answer :(

can you assist?

Answer 3

I can't guarantee that my answer will be correct.
can try
E= slope at x=1.10
\[(0.5,5.5)(2,2) \]
\[E= 1.84~~ \times 10^5 \frac{V}{m}\]
make sure to convert from cm to m
F=qE
F=(1.6 times 10^{-19}) (1.84 times 10^5) i
F= 2.94 times 10^{-14} i (N)

Answer 4

hm, that wasn't it either (your math seems correct though)

Answer 5

perhaps it is a webassign issue

Answer 6

thank you ^^

Answer 7

how do you put dot multiplication sign on web assign ?
i always use e
`2.94e-14`

Answer 8

technically both *10^__ and e___ should work :S

Answer 9

they both are same thing
my physics h.w doesn't take 10^

Answer 10

btw how did you get 3.733e-16 ?

Answer 11

slope = (2-5.5)/(2-0.5) = -2.3333 * 10^3 V

Answer 12

\(\mathbf E = - \dfrac{dV }{dx} ~ \mathbf i = - \dfrac{2 - 5.5}{2 - 0.5} \cdot \dfrac{10^3V}{cm} ~ \mathbf i = - \dfrac{7}{3} \cdot 10^5 ~ V/m~ \mathbf i\)

\(\mathbf F = q \mathbf E \approx \left( 1.6 \times 10^{-19} \right) \left( - \dfrac{7}{3} \cdot 10^5 \right) \mathbf i = 3.73 \times 10^{-14} \mathbf i \)

so conversion?!

Answer 13

oh duh I missed the cm to m conversion

Answer 14

i think that is what the little green apple was trying to say :/

Answer 15

that was correct thank you!

Answer 16

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Nnesha
I can't guarantee that my answer will be correct.
can try
E= slope at x=1.10
\[(0.5,5.5)(2,2) \]
\[E= 1.84~~ \times 10^5 \frac{V}{m}\]
make sure to convert from cm to m
F=qE
F=(1.6 times 10^{-19}) (1.84 times 10^5) i
F= 2.94 times 10^{-14} i (N)
\(\color{#0cbb34}{\text{End of Quote}}\)
i see what i did wrong
divided by (2-0.1)
but it is (2-0.5)