Question

help

Answer 1

i have denominator

Answer 2

so after factoring and applying the multiplications I get:

(x-4)(x+2) / [x(x+2)(x-2)] + 4(x) / [x(x+2)(x-2)]

Answer 3

so then I just add my numerators to get (x-4)(x+2) + 4x

^ now you can start expanding that

Answer 4

can you try doing the entire expansion in one comment ^^ it's a little less confusing that way

Answer 5

x^2
-8x
2x

Answer 6

you're forgetting about the constant term ^^"

Answer 7

remember foil

Answer 8

(x-4)(x+2) = x^2 + 2x - 4x - 8 = x^2 - 2x - 8

Answer 9

then we just add + 4x to get x^2 + 2x - 8 as the numerator

Answer 10

this expression factors out to get (x+4)(x-2) [not the same as the original, the signs are switched]

Answer 11

x^2-2x-8/x^2+2 is answer

Answer 12

x^2 + 2 is not the denominator

Answer 13

[x(x+2)(x-2)]

^ this is the denominator

Answer 14

oh ok

Answer 15

thank you for your help

Answer 16

then we write this out to get

(x+4)(x-2) / [x(x+2)(x-2)]

notice anything you can cancel out?

Answer 17

there's more lol

Answer 18

x-2

Answer 19

good, now we get (x+4)/ [ x * (x+2) ]

as our answer

Answer 20

so that's the finl answer

Answer 21

remember, you can use mathway to check your answers but your teacher is expecting all of the steps I have shown you

Answer 22

that's it

Answer 23

anyway I gotta go study for finals, good work today and take care