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Mathematics 8 Online
cookiemonster:

http://prntscr.com/h0zxjp

cookiemonster:

@563blackghost im glad your here on QC as well... pa is lagging a lot :(

563blackghost:

yea it is

cookiemonster:

so lets just work here bc QC never lags lol

563blackghost:

XD sure

cookiemonster:

so i posted the link to my question above^

563blackghost:

It's best for these kinds of problems to be plugged into your graphing calculator so that you can either make a graph from the table it provides or view the graph it makes. Try desmos.com

cookiemonster:

ok what do i apply in desmos?

563blackghost:

Well you click on `Start Graphing` and plug it in, here it is already plugged. https://www.desmos.com/calculator/itbyf1iieo

cookiemonster:

so it would be d?

cookiemonster:

graph d?

563blackghost:

yea

cookiemonster:

awesome next Determine the type of boundary line and shading for the graph of the inequality 4x + y > −6. Dashed line with shading on the side that includes the origin Solid line with shading on the side that does not include the origin Dashed line with shading on the side that does not include the origin Solid line with shading on the side that includes the origin

563blackghost:

\(\bf{>~or~<}\) are dashed, while as \(\bf{\ge~or~\le}\) are solid. So we can rule out B and D.

cookiemonster:

ok... would it be A?

563blackghost:

That is right :)

cookiemonster:

Simplify cube root of 5 over fourth root of 5. 5 to the power of 1 over 4 5 to the power of 1 over 12 5 to the power of 7 over 12 5 to the power of 4 over 3

cookiemonster:

\[\frac{ ^3 \sqrt{5} }{ ^4\sqrt{5} }\]

cookiemonster:

there is the problem so you can see it better

563blackghost:

We would multiply the roots to each other. \(\Large\bf{\frac{\sqrt[3]{5}}{\sqrt[4]{5}} \rightarrow \sqrt[3 \times 4]{5}}\) This simplifies to be \(\large\bf{\sqrt[12]{5}}\). We would apply \(\large\bf{a^\frac{1}{n}=\sqrt[n]{a}}\). \(\Large\bf{\sqrt[12]{5} \rightarrow 5 ^{\frac{1}{12}}}\)

cookiemonster:

http://prntscr.com/h11mbl

cookiemonster:

@563blackghost

563blackghost:

Apply this \(\Large\bf{a^\frac{b}{c} \rightarrow \sqrt[c]{a^{b}}}\). What would the answer be?

cookiemonster:

um... i dont get it

563blackghost:

Let's do an example. If I have the problem \(\large\bf{4^{\frac{5}{3}}}\) we would place it as \(\large\bf{\sqrt[3]{4^{5}}}\), we simplify to get \(\large\bf{\sqrt[3]{20}}\).

cookiemonster:

oh ok let me see if i can do it

cookiemonster:

when i simplified i got 2 4/3 the same thing .. your gonna have to show me how you do it bc i dont know

563blackghost:

\(\Large\bf{2^{\frac{4}{3}} \rightarrow \sqrt[3]{2^{4}}}\)

cookiemonster:

i tried to simplify that .... but i just get 2 4/3

563blackghost:

You are probably using a calculator to simplify it. What is \(\large\bf{2^{4}}\)?

cookiemonster:

16

563blackghost:

Correct! So it is \(\large\bf{\sqrt[3]{16}}\).

cookiemonster:

ohhhh wow i totally like over thought it lol

cookiemonster:

A function is shown below: f(x) = (1.07)^x What does the function represent? Exponential growth of 7% Exponential decay of 7% Exponential growth of 93% Exponential decay of 93%

cookiemonster:

is it A?^

563blackghost:

x'D just a bit I would say you are correct :)

cookiemonster:

http://prntscr.com/h11zra

563blackghost:

The best way I think to solve this is plug in the point into the equations (cause converting them all is a bit too much). The one that is the answer is the one in where the outcome is the same.

cookiemonster:

ummmm is it B?

563blackghost:

Not quite. If I plug in the point \({(2,−6)}\) into the first equation it would be false. \(\large\bf{2-2(-6)=14 \neq -10}\)

563blackghost:

Let's go down the list, let's try A. \(\large\bf{2+2(-6)=10~~ \checkmark}\) Let's try the second equation. \(\large\bf{3(2)-(-6)=12~~\checkmark}\) A is the answer.

cookiemonster:

ohhhhhh ok :) http://prntscr.com/h124qi

cookiemonster:

i think its d^ please check

563blackghost:

O.O Never seen these kinds of questions...freaky Let me check.

cookiemonster:

lol ok

563blackghost:

I would say you are correct, but I think it best if @Vocaloid can check.

cookiemonster:

ok for now lets continue

563blackghost:

sure

cookiemonster:

The following function represents the value of a house, in dollars, after x years: f(x) = 242,000(1.04)^x What does 242,000 represent? The present value of the house The value of the house after x years The increase in the value of the house each year The increase in the value of the house after x years

563blackghost:

Just to let you know I need to go in about 5 minutes :(

563blackghost:

This function is set-up as \(\large\bf{f(x)=ab^{x}}\). In which \(\large\bf{a}\) represents `the initial value` or `the present`.

cookiemonster:

ok so... it would be c?

563blackghost:

No it is A, since it states to be `the present value`.

cookiemonster:

ohhh ok :) The functions f(x) and g(x) are described using the following equation and table: f(x) = 4(1.02)x x g(x) −1 −4 0 6 1 8 2 10 Which statement best compares the y-intercepts of f(x) and g(x)? The y-intercept of f(x) is equal to the y-intercept of g(x). The y-intercept of f(x) is equal to 2 times the y-intercept of g(x). The y-intercept of g(x) is equal to 2 times the y-intercept of f(x). The y-intercept of g(x) is equal to 2 plus the y-intercept of f(x).

cookiemonster:

is it d?^

563blackghost:

Is that \(\large\bf{4(1.02)^{x}}\)?

cookiemonster:

yes

563blackghost:

D is correct, I was overthinking it x'D

cookiemonster:

hehe next Find an equivalent function to f(x) = 4(7)^2x. f(x) = 28^2x f(x) = 4(49)^x f(x) = 196^x f(x) = 16^x(49)^x

563blackghost:

This is set as \(\large\bf{4(7)^{2x}}\) if we simplify \(\large\bf{7^{2}}\) we will get the simplified function. \(\large\bf{4(7)^{2x} \rightarrow 4(49)^{x}}\)

cookiemonster:

so b?

563blackghost:

Yea

cookiemonster:

okay last one i believe The graph of f(x) = (0.5)^x is replaced by the graph of g(x) = (0.5)^x − k. If g(x) is obtained by shifting f(x) down by 7 units, the value of k is ________.

563blackghost:

This is a trick question. You see the format of this equation is \(\large\bf{g(x)=b^{x}+c}\). In where \({b}\) is \({0.5}\) and \({k}\) is \({c}\). We are told the function is `shifted down 7 units` which is applied as \(\large\bf{g(x)=b^{x}-7}\).So the value of \({k}\) is \(\bf{\color{red}{7}}\).

cookiemonster:

ok thank you so muchhh!!

563blackghost:

no problem ^.^

563blackghost:

What did you get?

cookiemonster:

100% :) im so happy

563blackghost:

|dw:1508787046679:dw|

cookiemonster:

hehe! you're the best :) thanks so much for helping me out i couldnt have done it without you

563blackghost:

your very welcome ^.^

cookiemonster:

:) are you good at history by any chance??? :)

563blackghost:

Kind of, like I would say about 70% good. ~~~ Well I am over my time by 30 minutes (didn't notice O.o). I gotta go, good luck on the rest of your work!

cookiemonster:

hehe ok thanksss!!! :)

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