Question

This is a doozy of an assignment plz help

Answer 1

@Vocaloid @Zeke When you guys have time

Answer 2

You have been asked by the police to find one of the three locations the Acute Perps gang is likely to hit in the coming weeks. Because the gang sticks to a triangular pattern, the locations could be a translation, reflection, or rotation of the original triangle. Choose one of the following transformations to help locate the gang:

Translation using SSS
Reflection using ASA
Rotation using SAS
After you have selected the one transformation you will be completing, go to step 2 for detailed directions.

Answer 3

I', choosing Translation

Answer 4

If you chose translation, use the coordinates of your transformation along with the distance formula to show that the two triangles are congruent by the SSS postulate. You must show all work with the distance formula and each corresponding pair of sides to receive full credit.

Answer 5

Then this is what need to be submitted

Answer 6

The three ordered pairs, with labels, of the congruent triangle you created using your transformation (Make sure to indicate which transformation was chosen.)
All work for any corresponding sides using the distance formula, and clear labels
All work for any corresponding angles (shown by use of a compass and straightedge or the slope formula)
The answer to the question that matches your transformation.

Answer 7

does it tell you how much to translate it by?

Answer 8

One sec

Answer 9

No it doesnt honestly

Answer 10

Not that i can see

Answer 11

Just gives me that picture up there

Answer 12

first step would be to write down the coordinates of the original 3 points

Answer 13

Ok

Answer 14

you can label them C, W, and G for short

Answer 15

W (-2,-3) C (3,6) G (-3,6)

Answer 16

flip the x and y coordinates for C and G

Answer 17

Oh ok

Answer 18

C should be (6,3) and G is (6,-3)

Answer 19

Ok

Answer 20

to make things simple, pick a number (like 5) and add that to one of the coordinates

Answer 21

so, for every y-coordinate, you could add 5 to get your C' G' and W'

Answer 22

this counts as a translation up by 5 units

Answer 23

Ok

Answer 24

C (6,8) Right?

Answer 25

good

Answer 26

G (6,2)

Answer 27

[label the transformed points as C', W' and G' instead of C W and G so it's less confusing]

Answer 28

but yeah you have the right idea

Answer 29

W' (-2,2)?

Answer 30

good, now try drawing your C' W' and G' and the new triangle should look the same as the old one

Answer 31

Ok

Answer 32

after that, it's the tedious part - using the distance formula to calculate all six triangle sides ;;

Answer 33

I have no clue how to do that XD

Answer 34

so let's just focus on WG and W'G' for now

Answer 35

Ok

Answer 36

Oh Jesus

Answer 37

So just plug it in right?

Answer 38

yeah basically

W = (-2,2) and G = (6,-3)

you would let x1 = -2, x2 = 6
y1 = 2, y2 = -3

and plug them into the formula

Answer 39

OH ok

Answer 40

to make it a bit easier to understand:

1. subtract the x-coordinates, then square the result
2. subtract the y-coordinates, then square the result
3. add your numbers from step 1 and step 2
4. take the square root of step 3

Answer 41

Ok

Answer 42

your answer should be 8 for WG ~and~ W'G'

Answer 43

Ok

Answer 44

So what about C?

Answer 45

for CG and C'G' the distance is 6 (make sure to show your work though)

Answer 46

Ok np will do thanks

Answer 47

What would this site be without you XD

Answer 48

and for CW and C'W' the distance is 10

Answer 49

label all six sides with the appropriate distance and show your calculations (this is super tedious sorry ;_;)

Answer 50

Now what do I do with that info just those are the answers?

Answer 51

Oh

Answer 52

Well it's not a simple exam I'm basically expecting this haha

Answer 53

It like an assignment my teacher asks for on a discussion baes assesment

Answer 54

once you show that CW = C'W', CG = C'G', and WG = W'G' that should be sufficient proof by SSS

Answer 55

Alright is it okay if I check back with you on my answers later? I gotta go take a shower XD

Answer 56

yeah sure I'll be on for maybe 2-3 more hours :

Answer 57

Rip m8

Answer 58

@Vocaloid So I do this for every combination of points?

Answer 59

yep, there should be 6 distances total

Answer 60

Ok

Answer 61

So we did W and G

Answer 62

Now I need G and C and W and C

Answer 63

Right?

Answer 64

good

Answer 65

then after that it would be W'G', G'C' and W'C'

Answer 66

Oh God ok

Answer 67

CG= 3.4?

Answer 68

your distances should be whole numbers ^^" I can do an example calculation if it makes things easier

Answer 69

Gimme a sec

Answer 70

Lemme explain what I did

Answer 71

I did steps one and two and got this (6,2) (6,8)=(0,-12)

Answer 72

^ that's C and C'

Answer 73

Wait hm?

Answer 74

you should be finding CG and C'G' not CC'

Answer 75

Okey? Thats weird

Answer 76

so your points would be C and G

Answer 77

so your original side lengths are CG, WG, and WC
your new sides are C'G', W'G', and W'C'

so you should find the distance between C-G, W-G, W-C, etc.

Answer 78

So do it again in reverse?

Answer 79

Cause I did it GC

Answer 80

the two points you picked weren't C and G

Answer 81

Point C is (6,8) right?

Answer 82

that's C' not C

Answer 83

C (without the dash mark) is just the point C on the original graph

Answer 84

Oh i think I get it C' is what we worked out

Answer 85

I can walk you through a sample calculation if it makes things easier?

Answer 86

Sure I guess

Answer 87

so C = the original point on the graph = (6,3)
C' = point C shifted up to get (6,8)

Answer 88

OH I FORGOT THE ADD 5

Answer 89

OK

Answer 90

point G = (6,-3)

Answer 91

so C-G distance =

sqrt( (6-6)^2 + (3 - (-3)^2 ) = sqrt(6^2) = 6

Answer 92

So do (6,8) + (6,-3) <--- after I work them out?

Answer 93

Subtract the X's and y's then square them then add them together then square root them?

Answer 94

so C' = (6,8) and G' = (6,2) so calculate the distance between these

Answer 95

yeah basically, just be careful with parentheses

Answer 96

I can work it out on graph paper so you at least have an answer key to look at

Answer 97

That would be ideal XD

Answer 98

So it should be (0,6) right (Not done just saying am I doing good so far)

Answer 99

Oh wait gotta square them hold up

Answer 100

(0,36) right?

Answer 101

your distance should be a single number not a (x,y) point

Answer 102

yeahIwasrightthefirstime Cg is 6

Answer 103

Ok so the answer is just 36?

Answer 104

To C'G'

Answer 105

6, because you take the square root at the end

Answer 106

Oh true missed that XD

Answer 107

^ worked out solution just in case I fall asleep on you

Answer 108

JESUS CHRIST I HAVE DONE BARELY ANYTHING

Answer 109

drawing & labeling a diagram will help keep your coordinates straight

Answer 110

Ok

Answer 111

So now since you did the work Smh now I have to plot them? Right

Answer 112

yeah basically (make sure you understand my work though, that's the important part)

Answer 113

I memorized the steps for next time thank yew for teaching me them

Answer 114

I will see if I can do the next one on my own

Answer 115

Is shadow good at math?

Answer 116

I think they should be able to handle this ^^

Answer 117

Ok thanks for the help Voca you are a lifesaver