Bearclaws72:

This is a doozy of an assignment plz help

10 months ago
Bearclaws72:

@Vocaloid @Zeke When you guys have time

10 months ago
Bearclaws72:
10 months ago

Bearclaws72:

You have been asked by the police to find one of the three locations the Acute Perps gang is likely to hit in the coming weeks. Because the gang sticks to a triangular pattern, the locations could be a translation, reflection, or rotation of the original triangle. Choose one of the following transformations to help locate the gang: Translation using SSS Reflection using ASA Rotation using SAS After you have selected the one transformation you will be completing, go to step 2 for detailed directions.

10 months ago
Bearclaws72:

I', choosing Translation

10 months ago
Bearclaws72:

If you chose translation, use the coordinates of your transformation along with the distance formula to show that the two triangles are congruent by the SSS postulate. You must show all work with the distance formula and each corresponding pair of sides to receive full credit.

10 months ago
Bearclaws72:

Then this is what need to be submitted

10 months ago
Bearclaws72:

The three ordered pairs, with labels, of the congruent triangle you created using your transformation (Make sure to indicate which transformation was chosen.) All work for any corresponding sides using the distance formula, and clear labels All work for any corresponding angles (shown by use of a compass and straightedge or the slope formula) The answer to the question that matches your transformation.

10 months ago
Vocaloid:

does it tell you how much to translate it by?

10 months ago
Bearclaws72:

One sec

10 months ago
Bearclaws72:

No it doesnt honestly

10 months ago
Bearclaws72:

Not that i can see

10 months ago
Bearclaws72:

Just gives me that picture up there

10 months ago
Vocaloid:

first step would be to write down the coordinates of the original 3 points

10 months ago
Bearclaws72:

Ok

10 months ago
Vocaloid:

you can label them C, W, and G for short

10 months ago
Bearclaws72:

W (-2,-3) C (3,6) G (-3,6)

10 months ago
Vocaloid:

flip the x and y coordinates for C and G

10 months ago
Bearclaws72:

Oh ok

10 months ago
Vocaloid:

C should be (6,3) and G is (6,-3)

10 months ago
Bearclaws72:

Ok

10 months ago
Vocaloid:

to make things simple, pick a number (like 5) and add that to one of the coordinates

10 months ago
Vocaloid:

so, for every y-coordinate, you could add 5 to get your C' G' and W'

10 months ago
Vocaloid:

this counts as a translation up by 5 units

10 months ago
Bearclaws72:

Ok

10 months ago
Bearclaws72:

C (6,8) Right?

10 months ago
Vocaloid:

good

10 months ago
Bearclaws72:

G (6,2)

10 months ago
Vocaloid:

[label the transformed points as C', W' and G' instead of C W and G so it's less confusing]

10 months ago
Vocaloid:

but yeah you have the right idea

10 months ago
Bearclaws72:

W' (-2,2)?

10 months ago
Vocaloid:

good, now try drawing your C' W' and G' and the new triangle should look the same as the old one

10 months ago
Bearclaws72:

Ok

10 months ago
Vocaloid:

after that, it's the tedious part - using the distance formula to calculate all six triangle sides ;;

10 months ago
Bearclaws72:

I have no clue how to do that XD

10 months ago
Vocaloid:

|dw:1508807902267:dw|

10 months ago
Vocaloid:

so let's just focus on WG and W'G' for now

10 months ago
Bearclaws72:

Ok

10 months ago
Bearclaws72:

Oh Jesus

10 months ago
Bearclaws72:

So just plug it in right?

10 months ago
Vocaloid:

yeah basically W = (-2,2) and G = (6,-3) you would let x1 = -2, x2 = 6 y1 = 2, y2 = -3 and plug them into the formula

10 months ago
Bearclaws72:

OH ok

10 months ago
Vocaloid:

to make it a bit easier to understand: 1. subtract the x-coordinates, then square the result 2. subtract the y-coordinates, then square the result 3. add your numbers from step 1 and step 2 4. take the square root of step 3

10 months ago
Bearclaws72:

Ok

10 months ago
Vocaloid:

your answer should be 8 for WG ~and~ W'G'

10 months ago
Bearclaws72:

Ok

10 months ago
Bearclaws72:

So what about C?

10 months ago
Vocaloid:

for CG and C'G' the distance is 6 (make sure to show your work though)

10 months ago
Bearclaws72:

Ok np will do thanks

10 months ago
Bearclaws72:

What would this site be without you XD

10 months ago
Vocaloid:

and for CW and C'W' the distance is 10

10 months ago
Vocaloid:

label all six sides with the appropriate distance and show your calculations (this is super tedious sorry ;_;)

10 months ago
Bearclaws72:

Now what do I do with that info just those are the answers?

10 months ago
Bearclaws72:

Oh

10 months ago
Bearclaws72:

Well it's not a simple exam I'm basically expecting this haha

10 months ago
Bearclaws72:

It like an assignment my teacher asks for on a discussion baes assesment

10 months ago
Vocaloid:

once you show that CW = C'W', CG = C'G', and WG = W'G' that should be sufficient proof by SSS

10 months ago
Bearclaws72:

Alright is it okay if I check back with you on my answers later? I gotta go take a shower XD

10 months ago
Vocaloid:

yeah sure I'll be on for maybe 2-3 more hours :

10 months ago
Bearclaws72:

Rip m8

10 months ago
Bearclaws72:

@Vocaloid So I do this for every combination of points?

10 months ago
Vocaloid:

yep, there should be 6 distances total

10 months ago
Bearclaws72:

Ok

10 months ago
Bearclaws72:

So we did W and G

10 months ago
Bearclaws72:

Now I need G and C and W and C

10 months ago
Bearclaws72:

Right?

10 months ago
Vocaloid:

good

10 months ago
Vocaloid:

then after that it would be W'G', G'C' and W'C'

10 months ago
Bearclaws72:

Oh God ok

10 months ago
Bearclaws72:

CG= 3.4?

10 months ago
Vocaloid:

your distances should be whole numbers ^^" I can do an example calculation if it makes things easier

10 months ago
Bearclaws72:

Gimme a sec

10 months ago
Bearclaws72:

Lemme explain what I did

10 months ago
Bearclaws72:

I did steps one and two and got this (6,2) (6,8)=(0,-12)

10 months ago
Vocaloid:

^ that's C and C'

10 months ago
Bearclaws72:

Wait hm?

10 months ago
Vocaloid:

you should be finding CG and C'G' not CC'

10 months ago
Bearclaws72:

Okey? Thats weird

10 months ago
Vocaloid:

so your points would be C and G

10 months ago
Vocaloid:

so your original side lengths are CG, WG, and WC your new sides are C'G', W'G', and W'C' so you should find the distance between C-G, W-G, W-C, etc.

10 months ago
Bearclaws72:

So do it again in reverse?

10 months ago
Bearclaws72:

Cause I did it GC

10 months ago
Vocaloid:

the two points you picked weren't C and G

10 months ago
Bearclaws72:

Point C is (6,8) right?

10 months ago
Vocaloid:

that's C' not C

10 months ago
Vocaloid:

C (without the dash mark) is just the point C on the original graph

10 months ago
Bearclaws72:

Oh i think I get it C' is what we worked out

10 months ago
Vocaloid:

I can walk you through a sample calculation if it makes things easier?

10 months ago
Bearclaws72:

Sure I guess

10 months ago
Vocaloid:

so C = the original point on the graph = (6,3) C' = point C shifted up to get (6,8)

10 months ago
Bearclaws72:

OH I FORGOT THE ADD 5

10 months ago
Bearclaws72:

OK

10 months ago
Vocaloid:

point G = (6,-3)

10 months ago
Vocaloid:

so C-G distance = sqrt( (6-6)^2 + (3 - (-3)^2 ) = sqrt(6^2) = 6

10 months ago
Bearclaws72:

So do (6,8) + (6,-3) <--- after I work them out?

10 months ago
Bearclaws72:

Subtract the X's and y's then square them then add them together then square root them?

10 months ago
Vocaloid:

so C' = (6,8) and G' = (6,2) so calculate the distance between these

10 months ago
Vocaloid:

yeah basically, just be careful with parentheses

10 months ago
Vocaloid:

I can work it out on graph paper so you at least have an answer key to look at

10 months ago
Bearclaws72:

That would be ideal XD

10 months ago
Bearclaws72:

So it should be (0,6) right (Not done just saying am I doing good so far)

10 months ago
Bearclaws72:

Oh wait gotta square them hold up

10 months ago
Bearclaws72:

(0,36) right?

10 months ago
Vocaloid:

your distance should be a single number not a (x,y) point

10 months ago
Vocaloid:

yeahIwasrightthefirstime Cg is 6

10 months ago
Bearclaws72:

Ok so the answer is just 36?

10 months ago
Bearclaws72:

To C'G'

10 months ago
Vocaloid:

6, because you take the square root at the end

10 months ago
Vocaloid:
10 months ago

Bearclaws72:

Oh true missed that XD

10 months ago
Vocaloid:

^ worked out solution just in case I fall asleep on you

10 months ago
Bearclaws72:

JESUS CHRIST I HAVE DONE BARELY ANYTHING

10 months ago
Vocaloid:

drawing & labeling a diagram will help keep your coordinates straight

10 months ago
Bearclaws72:

Ok

10 months ago
Bearclaws72:

So now since you did the work Smh now I have to plot them? Right

10 months ago
Vocaloid:

yeah basically (make sure you understand my work though, that's the important part)

10 months ago
Bearclaws72:

I memorized the steps for next time thank yew for teaching me them

10 months ago
Bearclaws72:

I will see if I can do the next one on my own

10 months ago
Bearclaws72:

Is shadow good at math?

10 months ago
Vocaloid:

I think they should be able to handle this ^^

10 months ago
Bearclaws72:

Ok thanks for the help Voca you are a lifesaver

10 months ago