reason and proof http://prntscr.com/h1hni6
its all one problem
i know the QA=QA is reflexive
Love these XD Since QA bisects PQR then two congruent angles are created. Being \(\bf{\angle PQA \cong \angle RQA}\).
black ghost from pa!
indeed
ive always appreciated your help !
*bow* ;)
:)
so i was thinking for the second one
pqa=rqa for All right angles are congruent.
?
For Statement 2 that is correct.
Do you know what Statement 4 is?
For Statement 2 it can not be \(\bf{\triangle PQA \cong \triangle RQA}\) since we have not proven anything yet. It would be \(\bf{\angle PQA \cong \angle RQA}\), this is due to a angle bisector creating 2 congruent angles. The statement for 4 would be \(\bf{\angle QXA \cong \angle QYA}\) since the two angles are right angles, thus being congruent to each other. The reflexive property is correct for Reason 5.
That is read as `Statement 6` not 4 (they go by each row) just so we don't mix ourselves up. The reason is correct but the statement is not. \(\bf{AAS~Congruence~Theorem}\) is used only when proving a triangle. Since we solved by from an angle-angle-side we proved by \(\bf{ \triangle QXA \cong \triangle QYA}\).
Do you understand what I typed?
yes i do i was just confused wth the row and columns is this how its supposed to look now ? http://prntscr.com/h1hxsx
Looks good.
awesome thnx for your time !
np :)
im sorry i have one more are u still online ?
yea i am sorry i was helping another
take your time !
Looks amazing!
awesome !
Wait!
oh!
You got to switch two of them around, For the first blank of `Linear Pair Postulate` `Statement 3` it needs to be \(\bf{m \angle 2 + m \angle 3 = 180^{o}}\).
What was in place of `Statement 3` needs to be in `Statement 5`.
Other than that it looks golden.
thnx <3
np ;)
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