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Mathematics 15 Online
Sarah10:

reason and proof http://prntscr.com/h1hni6

Sarah10:

its all one problem

Sarah10:

i know the QA=QA is reflexive

563blackghost:

Love these XD Since QA bisects PQR then two congruent angles are created. Being \(\bf{\angle PQA \cong \angle RQA}\).

Sarah10:

black ghost from pa!

563blackghost:

indeed

Sarah10:

ive always appreciated your help !

563blackghost:

*bow* ;)

Sarah10:

:)

Sarah10:

so i was thinking for the second one

Sarah10:

pqa=rqa for All right angles are congruent.

Sarah10:

?

563blackghost:

For Statement 2 that is correct.

563blackghost:

Do you know what Statement 4 is?

Sarah10:

so this is how its supposed to look like http://prntscr.com/h1hs7o

563blackghost:

For Statement 2 it can not be \(\bf{\triangle PQA \cong \triangle RQA}\) since we have not proven anything yet. It would be \(\bf{\angle PQA \cong \angle RQA}\), this is due to a angle bisector creating 2 congruent angles. The statement for 4 would be \(\bf{\angle QXA \cong \angle QYA}\) since the two angles are right angles, thus being congruent to each other. The reflexive property is correct for Reason 5.

Sarah10:

is this for statement 4 http://prntscr.com/h1hssz

563blackghost:

That is read as `Statement 6` not 4 (they go by each row) just so we don't mix ourselves up. The reason is correct but the statement is not. \(\bf{AAS~Congruence~Theorem}\) is used only when proving a triangle. Since we solved by from an angle-angle-side we proved by \(\bf{ \triangle QXA \cong \triangle QYA}\).

563blackghost:

Do you understand what I typed?

Sarah10:

yes i do i was just confused wth the row and columns is this how its supposed to look now ? http://prntscr.com/h1hxsx

563blackghost:

Looks good.

Sarah10:

awesome thnx for your time !

563blackghost:

np :)

Sarah10:

im sorry i have one more are u still online ?

Sarah10:

http://prntscr.com/h1hzfu i did it all can you just tell me if im correct

Sarah10:

last choice left http://prntscr.com/h1hzum

563blackghost:

yea i am sorry i was helping another

Sarah10:

take your time !

563blackghost:

Looks amazing!

Sarah10:

awesome !

563blackghost:

Wait!

Sarah10:

oh!

563blackghost:

You got to switch two of them around, For the first blank of `Linear Pair Postulate` `Statement 3` it needs to be \(\bf{m \angle 2 + m \angle 3 = 180^{o}}\).

563blackghost:

What was in place of `Statement 3` needs to be in `Statement 5`.

563blackghost:

Other than that it looks golden.

Sarah10:

thnx <3

563blackghost:

np ;)

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