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Mathematics 12 Online
zarkam21:

IS this 3?

zarkam21:

1 attachment
zarkam21:

1 attachment
zarkam21:

@Vocaloid

Vocaloid:

hm I got something different try writing out your an = a1 + (n-1)d formulas for the 7th term and the 10th term

zarkam21:

the 7 is substituted for the d right

Vocaloid:

7 would be n

Vocaloid:

since we don't know a1 and d yet, leave those alone and substitute everything else

Vocaloid:

you should get one formula for a7 and one for a10

zarkam21:

okay a(7)= a1 + (7-1)d a(10)=a1+(10-1)d

Vocaloid:

good, now substitute 21 for a7 and 126 for a10 since these are given

Vocaloid:

21 = a1 + (7-1)d 126 = a1 + (10-1)d now subtract the two equations. you should be able to eliminate a1.

zarkam21:

each separate equations right

zarkam21:

21=+69(d)

Vocaloid:

first subtract the left hand sides 126 - 21 then subtract the right hand sides a1 + (10-1)d - [a1 + (7-1)d]

Vocaloid:

let me know what you get for each side

zarkam21:

3d

zarkam21:

and 105

Vocaloid:

good and if 3d = 105, then d = ?

zarkam21:

35

Vocaloid:

good, now we take that d value and substitute back into a7

Vocaloid:

21 = a1 + (7-1)(35) a1 = ?

zarkam21:

189

Vocaloid:

should be negative -189 ^^ but yeah that's your answer

zarkam21:

haha thank you

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