Question

math help

Answer 1

@Vocaloid

Answer 2

help?

Answer 3

you there

Answer 4

I'm going through the calculations

Answer 5

for the first problem pick a value of b (let's just say b = 0.5) and see what happens when x becomes very large or very negative

Answer 6

for example, if we have something like y = (0.5)^(-1000) what kind of number do we get? is it close to 0? infinity? negative infinity?

Answer 7

its 1.071 etc

Answer 8

so 0

Answer 9

don't forget the exponent

Answer 10

it ends up being 10^(31) so this is a very very large positive number

which means it approaches + infinity as x ---> -infinity

Answer 11

now try seeing what happens if you calculate x to be a very large positive number

say, y = (0.5)^(1000)?

Answer 12

i know 3 is a

Answer 13

the opposite

Answer 14

what does the function approach when x is very large?

Answer 15

-infinity? as x infinity

Answer 16

try calculating (0.5)^(100) and let me know what you get

Answer 17

i got 9.332 etc

Answer 18

make sure you are including the exponential part too

Answer 19

what does the exponent look like?

Answer 20

9.332636e

Answer 21

what is the part after the e?

Answer 22

-302

Answer 23

good, so if the exponent is very very negative that means this term is close to 0

Answer 24

so end behavior:

x --> -infinity, function --> infinity
x ---> infinity, function --> 0

pick the answer choice that matches

Answer 25

b?

Answer 26

awesome, good

Answer 27

so for the second problem, a reflection over y puts a negative sign right in front of x

Answer 28

is 2 d

Answer 29

awesome good

Answer 30

and 3 was a) like you said

Answer 31

4

Answer 32

use exponential form to evaluate logsub poenent 8 2

Answer 33

\[\log_{8} 2 \]

Answer 34

this?

Answer 35

yes

Answer 36

so 2 is your y-value and 8 is your b value

Answer 37

2 = 8^x

solve for x

Answer 38

1/3

Answer 39

good

Answer 40

oh lordy I would honestly just graph these and compare the graphs

Answer 41

oh lord

Answer 42

wolframalpha.com maybe

Answer 43

7 is good

Answer 44

so for 8 you want to split the quotient into a difference (basically the opposite of what you did for 7)

Answer 45

and then you can move the 2 on the x^2 to the front of the log

let me know what you get

Answer 46

b the answer?

Answer 47

I remember studying this over the summer

Answer 48

b correct?

Answer 49

I think that's right yeah

Answer 50

@Vocaloid

Answer 51

@Vocaloid

Answer 52

9 is right

Answer 53

still working on 10

Answer 54

for 10, first re-write both sides in base 2 to eliminate the log(2)

Answer 55

and then write both sides in base 5 to eliminate log_5

Answer 56

so c ?

Answer 57

?????

Answer 58

nvm c is right

Answer 59

it is yay