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|dw:1509935374943:dw|
let n = 50 and calculate an
152
good, now find a1
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-152+2sn/n
use the original formula to find an when n = 1
an = 3n + 2
5
good, now use your a1 and a50 values to find sn
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wait a1=5 and an=50
or the other way around
scroll up, we calculated an
an=152 and a1=5?
good
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11932
n = 50 a1 = 5 a50 = 152 sn = (n/2)(a1+a50) = ?
5+50 right
a1 = 5 a50 = 152 a1 + a50 = ?
25*55
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1375
good, now (n/2)(a1+a50) = ?
well n = 5 right
how many terms are we calculating the sum for?
50
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50/2=25
good, so n = 50
so now we have: n = 50 a1 = 5 a50 = 152 sn = (n/2)(a1+a50) = ?
(50/2)(5+152) (25)(157)
good, and that equals...?
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3925
good, that's your answer
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