Question

Help please

Answer 1

so for part A it... seems like they just want you to copy g(x) = x^2 + 2, just without the g(x) = part

so just x^2 + 2

Answer 2

and then for b, take f(x) = 1/(x-5) and then just replace "x" with "x^2+2"

Answer 3

\[f(x^2+2)=\frac{ 1 }{ x^2+2 }\]

Answer 4

don't forget the -5 part

Answer 5

should be 1/(x^2+2-5)

Answer 6

\[f(x^2+2)=\frac{ 1 }{ x^2+2-5) }\]

Answer 7

good, make sure to simplify that though

Answer 8

2-5 = -3

Answer 9

so just x^2-3

Answer 10

for the denominator

Answer 11

yes

Answer 12

okay for part II A

Answer 13

I would just write f(6)=

Answer 14

the equation we came up with

Answer 15

for f(6) use the original equation and calculate it when x = 6

Answer 16

so f(x) = 1/(x-5) = 1/(6-5)

Answer 17

do I simplify this

Answer 18

or as is

Answer 19

simplify

Answer 20

\[f(X)=\frac{ 1 }{ x-5 }=1\]

Answer 21

awesome, now let x = 1 and substitute this into g(x) = x^2 + 2

Answer 22

\[f(1)=\frac{ 1 }{ 1-5 }\]

Answer 23

using g(x) not f(x) ^^

Answer 24

when x = 1 g(x) = ?

Answer 25

g(x) = x^2 + 2

let x = 1 and find what g(x) equals

Answer 26

g(1)=1^2+2

Answer 27

good and that equals..?

Answer 28

3

Answer 29

good so that's your ans. for part II B)

Answer 30

so a is f(x)=1/(x-5)=1
and b is 3

Answer 31

good but I would write a as f(6) = 1/(6-5) = 1 to be more specific

Answer 32

otherwise, yeah.