Question

Help please

Answer 1

@563blackghost

Answer 2

@Vocaloid

Answer 3

@Vocaloid

Answer 4

For piecewise fumctions you use the inequalities to determine which row of the function you use for the given x value

Answer 5

Do for x = 0 would this be the top row or the bottom row?

Answer 6

top

Answer 7

Good so f(0) =?

Answer 8

x^2+x<=1

Answer 9

There is no reason to add the functions together

Answer 10

oh how would I join them

Answer 11

We have established that f(x) = x^2 for x = 0

So evaluate f(0)

Answer 12

x^2

Answer 13

What does x^2 equal when x = 0

Answer 14

Replace x with 0 and evaluate x^2

Answer 15

Anyway I got to go, I can help you with the graphing after class if you're still free

Answer 16

okay when you are back, we can finish this

Answer 17

to graph the function you would just follow the instructions given in part II

Answer 18

for example, for IIA it asks you to graph the first function normally (as if it were a normal function not a piecewise function)

Answer 19

so graph f(x) = x^2

Answer 20

okay for number 7 part a

Answer 21

I would write f(x) = x^2 for x = 0

Answer 22

yes

Answer 23

and then for part b

Answer 24

I would write f(0)=0^2

Answer 25

?

Answer 26

yes but make sure to evaluate what 0^2 is equal to

Answer 27

0?

Answer 28

so f(0)=0

Answer 29

yes

Answer 30

okay now for the graphing part

Answer 31

just graph f(x) = x^2

Answer 32

yes for part IIA

Answer 33

good.

Answer 34

Now for IIB I would graph f(x)=x<=1

Answer 35

you would graph f(x) = 2x + 1

Answer 36

since that's the function for the second row

Answer 37

okay did that.

Answer 38

now for IIc

Answer 39

now you just go back to your graph and erase the parts that aren't included on the domain

Answer 40

for example, for f(x) = x^2 for x<=1 you would just erase the graph where x is greater than 1

Answer 41

so erase everything except for the black shaded region

Answer 42

imagine an imaginary line at x = 1 and erase the graph of x^2 on the right of the line

Answer 43

okay

Answer 44

did that

Answer 45

now for 2x + 1 erase the graph where x < 1

Answer 46

you want to erase the graph where x is ~~less~~ than 1

Answer 47

oh okay so the opposite

Answer 48

yes

Answer 49

you have the right idea but check the values of your graph

Answer 50

for example, when x = 1 x^2 = 1 so the x^2 graph should have a point at (1,1)

Answer 51

and when x = 1, 2x+1 = 3 so the graph of 2x+1 should have a point at (1,3)

Answer 52

the parabola stops at (1,1) and the straight line starts at (1,3)

Answer 53

@

Answer 54

good, that's it for part IIb

Answer 55

you mean c

Answer 56

;p

Answer 57

yeah

Answer 58

okay next, the last part

Answer 59

is to place open and closed circles

Answer 60

anyway for part D, any inequality with > or < gets an open circle and >= and <= get closed circles

Answer 61

so the parabola gets a closed circle at (1,1) and the line gets an open circle at (1,3)

Answer 62

good that's it