Question

A is yes?

Answer 1

yes

Answer 2

okay for the second part would I just substitute something in for A

Answer 3

you are already given A

Answer 4

multiply the matrix A by 3

Answer 5

a value in A

Answer 6

3(2)=6

Answer 7

yes, now keep going for the entire matrix

Answer 8

3(2)=6
3(-1)=-3
3(0)=0
3(0)=0
3(5)=15
3(0.3)=0.9
3(1)=3
3(4)=12
3(10)=30

Answer 9

good, now put these into a new matrix, making sure to preserve the original order

Answer 10

I need to go, I'm starting to feel ill and I need some medication

Answer 11

for part IC just add the matrices 3A and B
and for part IIA look up matrix multiplication

Answer 12

@Nnesha

Answer 13

@Hero

Answer 14

@Vocaloid are you okay?

Answer 15

Which problem are you stuck on @zarkam21

Answer 16

The picture I posted, is that correct

Answer 17

How did you arrive at your answer for C? Can you show me the steps?

Answer 18

Well the original value given is 3A, I simply substituted A for one of the values from the "A" Matrix then since that equation is 3(A) +B I used a value from the B Matrix to establish the equation 3(2)-5

Answer 19

3(2)+5

Answer 20

By the way, the value of 3A + B will be a 3 x 3 matrix.

Answer 21

oh so I have to create a matrix for it not an equation

Answer 22

It is simply asking you to take matrix A multiply its value by 3, then add that result to B. As I said, your result should be a 3 x 3 matrix.

Answer 23

so multiply every Matrix a value by 3 and then add those to create a new matrix

Answer 24

thanks Hero I'm feeling a lot better now

do you want to continue helping zarkam or should I take over

Answer 25

ok, so for part B be careful with your notation. you have stated that A = [the matrix] but it should actually be 3A = [your matrix] since you multiplied A by 3 to get the new matrix

Answer 26

also the 3(2) = 6 is not necessary I would probably remove that

Answer 27

okay so for #9 part I the answer is yes

Answer 28

yes

Answer 29

and you are saying for 9B just the matrix is necessary not 3(2)=6

Answer 30

righto

Answer 31

Yes, you can take over. Glad you're back but I'm concerned about your health. Do you consume organic foods and drink filtered water?

Answer 32

it should also be labelled as 3A not just A

Answer 33

I can talk to you later Hero ^_^"

Answer 34

like this for part b

Answer 35

yup good

Answer 36

then for part c, to add 3A + B you would create a new 3x3 matrix and add the corresponding entries of 3A and B

Answer 37

for example, the first entry would be 6 + 5 = 11 so you would put 11 as the first entry in your new matrix

Answer 38

good so that's your answer for C (erase the other stuff you've written)

Answer 39

sorry I am doing other work as well, which is why the replies are not fast

Answer 40

it's ok, i'm doing a bit of multitasking myself ^^

Answer 41

okay now part II

Answer 42

It would actually be no right

Answer 43

because how can the c and a matrix combine

Answer 44

hold on

Answer 45

Of course

Answer 46

actually, you can multiply these two matrices

to determine this, you would write out the dimensions of C and A

Answer 47

so it is yes

Answer 48

C is a 1 x 3 matrix
A is a 3 x 3 matrix

Answer 49

yes

Answer 50

(1 x 3) times (3 x 3)

since the "inner dimensions" are the same you can multiply these

Answer 51

and the answer to this would be the answer to PArt II B

Answer 52

okay so the inner dimensions are for matrix a

Answer 53

and the outside for matrix c

Answer 54

oh okay I get it

Answer 55

just use the dimensions to create two types of equations almost and then use the inner dimension to solve

Answer 56

27

Answer 57

I'm not exactly sure what you mean here

Answer 58

I have only done part A so far

Answer 59

I mean that you use the number of rows x columns to create two pairs

Answer 60

and then multiply the inner numbers

Answer 61

keep in mind this is only to determine whether the product can be calculated, this has nothing to do with the actual product

Answer 62

alright so this is just an example, if I am understanding correctly

Answer 63

we cannot find CA using this information

Answer 64

this is how to find part A which only asks whether CA can be calculated or not

Answer 65

anyway, to find CA, we first consider: row 1 of matrix C * column 1 of matrix A [this can be hard to explain so bear with me ;_;]

Answer 66

so you would multiply the numbers connected by the arrows and add the products to get

1(2) + 3(0) + 5(1)

Answer 67

which is 7, and this becomes the first entry in the product matrix (still not done yet)

Answer 68

and then you would keep repeating this process for columns 2 and 3 of matrix A

Answer 69

I hope this makes sense, I have a hard time explaining this concept through words

Answer 70

Well lets see how well you did 😅

Here is what I got

Answer 71

7
34
50.9

Answer 72

all in a matrix

Answer 73

good, and to determine the dimensions of this matrix we will look back at our part A work

Answer 74

which means you would put these 3 numbers into a matrix with 1 row and 3 columns

Answer 75

\(\color{#0cbb34}{\text{Originally Posted by}}\) @zarkam21
7
34
50.9
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 76

talking about these three numbers sorry

Answer 77

okay so for

Answer 78

so this is the answer for 9II B

Answer 79

good that's it