Question

Please help

Answer 1

Ooo linear equations!

Have you changed it into slope-intecept yet?

Answer 2

oh yeahhhhhhhhh

Answer 3

nope, one second e.e

Answer 4

y=(-1/2)x+3

Answer 5

Nice :)

So for two lines to be parallel they much contain the same slope and different y-intercepts. For perpendicular lines the slope are reciprocal.

So we have a slope of \(\bf{\large-\frac{1}{2}}\) the parallel slope would be \(\bf{\large-\frac{1}{2}}\).

We have a slope of \(\bf{\large-\frac{1}{2}}\) and our perpendicular slope would be flipped fraction and changed sign...\(\bf{\large{2}}\).

Which can we determine already is parallel?

Answer 6

line q

Answer 7

q?

are we looking at the same diagram, cause none are stated as line q.

https://assets.questioncove.com/attachments/1510169903-5a035d1c7d3539d95416f800-image.png

Answer 8

crap i was on the wrong page e.e ignore that

Answer 9

XD ohhh ok

Answer 10

the 1st one x'D

Answer 11

nice :D

Answer 12

Now if we look at the form of \(\bf{x+2y}\) we know it ends with a slope of \(\bf{-\frac{1}{2}}\) correct?

Then any with this form will also end with the same slope. Which contains the same form?

Answer 13

the last one?

Answer 14

yes!

Answer 15

Now it's best to change the second and third into slope-intercept form. Can you do that?

Answer 16

2nd is y=2x-4

Answer 17

so x+2y=-2 is Parallel to y=(-1/2)x+3?

Answer 18

yup.

Answer 19

If you change it into slope-intercept it will contain the same slope, so yes.

Answer 20

Correct, the second is `y=2x-4`. How would this be classified?

`REMEMBER parallel lines have similar slopes and perpendicular lines are reciprocal.`

Answer 21

perpendicular i think

Answer 22

Correct!

Answer 23

Now if we change the third one into slope-intercept it would become \(\large\bf{y=\frac{1}{2}x+1}\). Perpendicular lines are reciprocal `2` and parallel lines are the same `-1/2` the slope of the this equation is neither of these. So it is classified as neither.

Answer 24

ah oki cx

Answer 25

i have two more questions if thats oki, i just need you to explain how to do it though

Answer 26

if you can of course cx

Answer 27

I would love too, but I have to go and pick up my bro from school and my sis. I won't be back for more than an hour.

If you still need help when I get back I can!

Answer 28

Oki thank you cx and hope that goes well <3 cx

Answer 29

^.^ your welcome