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Mathematics 20 Online
kaylak:

help

kaylak:

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kaylak:

@Hero

Vocaloid:

for #3 you would apply [\log_{b} \] to both sides

Vocaloid:

(should be log base b)

Vocaloid:

and then for #4 consider the fact you are multiplying x by 2 (a horizontal transformation) and subtracting 4 from x (another horizontal transformation)

kaylak:

thank you i'll show you my answers so far

kaylak:

@Vocaloid

kaylak:

@Vocaloid is3 c

Vocaloid:

good

kaylak:

yay

kaylak:

give me a sec i'll show you my first 4 answers in a bit

kaylak:

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kaylak:

is it too blurry

kaylak:

@Vocaloid

kaylak:

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kaylak:

4 is b?

Vocaloid:

I don't think #1 is right

kaylak:

that's what another person here told me i didn't think so either

kaylak:

i thought c

Vocaloid:

as a hint: use your exponent rules to re-write 4^(1-x) as a quotient

Vocaloid:

good, c is right

kaylak:

see i do know some of this and someone said i was wrong

kaylak:

is 2 right or is it d i originally had d someone else said d is wrong

Vocaloid:

2 is c, good

Vocaloid:

the reason you eliminate the negative solution is because your log functions each need to be positive or 0

kaylak:

ok so the first 3 are c lol

Vocaloid:

check 4 again

kaylak:

4 b?

kaylak:

ok

Vocaloid:

(x-h) means a horizontal shift by h units to the right

kaylak:

so then 2 it is a shift by 2

Vocaloid:

look at the original problem

kaylak:

i graphed it though?

kaylak:

how does it not shift 2 units though every direction it does

kaylak:

and it shrinks?

Vocaloid:

kaylak:

it's 2x-4?

Vocaloid:

it's easier to see the shift if you only consider one transformation at a time.

kaylak:

ok

Vocaloid:

if you try plotting log(2x-4) it can be confusing to see the shift especially with a bad scale/axes

kaylak:

so 4 compressed

Vocaloid:

no

kaylak:

you have f and g backwards?

kaylak:

now I'm confused ?

Vocaloid:

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Vocaloid:

switched

kaylak:

ok horizontally it stretches it appears

kaylak:

right?

Vocaloid:

I have only applied one transformation ( the shift to the right by 4 units )

Vocaloid:

I have not applied the stretch/shrink yet

kaylak:

ok I'm tried graphing into mathway one minute it doesnt want to graph and the next idk

Vocaloid:

it's very hard to see graphically but it gets compressed horizontally

Vocaloid:

you also need to be able to do these algebraically without looking at graphs

kaylak:

so I was right about compression

Vocaloid:

when you multiply x by a number greater than 1 it's a horizontal compression, yes

kaylak:

ok and the 4 kinda gives it away that it is 4 and the only options are to the right

kaylak:

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Vocaloid:

combine the two logs inside the brackets into one log expression using your log rules

kaylak:

is it b?

kaylak:

a is wrong d doesn't make sense and c i didn't get -3 as a bottom

Vocaloid:

good, b

kaylak:

yay

Vocaloid:

I don't remember how to do 6, but it would involve a change of base

kaylak:

i am basically dividing what i got for a decimal to see which one it is hold on

kaylak:

it's c

kaylak:

the decimal is a negative so that means a or c and the decimal is -1.19....

Vocaloid:

sure, go with that

kaylak:

7 is just graphing to see what the graph is so i figured that out

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kaylak:

is taht supposed to be 0.5?

Vocaloid:

probably

kaylak:

it would be c right

Vocaloid:

I'm actually getting a bit too exhausted to process this properly @Hero could you spare a moment?

kaylak:

d wouldn't make sense -5 to -4

kaylak:

any negative number value for x would make the left side greater in value than the right if it is positive it would make the right side larger

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