Last question ughhh
g(x) is just the expression within the square root symbol
3x-4?
good
f(x) is just what is being applied to g(x), which is just taking the square root
so f(x) = sqrt(x)
by defining f(x) and g(x) this way, we are making f(g(x)) = sqrt(3x-4)
for part I do I put the sqrt symbol or just 3x-4
no square root symbol just 3x - 4
okay
so for part II
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid so f(x) = sqrt(x) \(\color{#0cbb34}{\text{End of Quote}}\)
that's II
so f(x)=sqrt(x) is II
yes
soo for part III you are just verifying that f(g(x)) = sqrt(3x-4) so you would just start with f(x) = sqrt(x) and then substitute g(x) for x inside f(x)
wait g(x) is 3x-4 right
yes
f(3x-4)=sqrt(3x-4)
awesome, so you have completed the verification. to answer this question you would just show your work for: f(x) = sqrt(x) and then f(g(x)) = sqrt(g(x)) = sqrt(3x-4)
well they are only asking for the verification right?
yes
so I don't have to put the solved part
well, you would still have to show your work
"verify" means they want you to show that the original statement is true using your own calculations/reasoning/etc.
Right, I understand what you're saying
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid awesome, so you have completed the verification. to answer this question you would just show your work for: f(x) = sqrt(x) and then f(g(x)) = sqrt(g(x)) = sqrt(3x-4) \(\color{#0cbb34}{\text{End of Quote}}\)
so I would just write what you have here to show work ?
yeah
okay thank you so much
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