Help please on this SAT question I am practicing, Do not understand it and am freaking out
Post the question please. :)
^
Ill try to help if I can :3
@Hero get ready to work your magic
@Vocaloid @Hero
ohhhh well I should just leave I know nothing about math xD
You need to find the solution to the system of equations this means that you need to find the numerical value of a and the numerical value of b and then subtract b-a
Yes I understand that
(a,b) is equivalent to (x,y)
Yes, are you familiar with solving system of equations?
Yes but the (b+a) and (b-a) is confusing me in the problem
Don't be confused by it, solve it as you normally would, distribute the 3 to (a+b)
\[1.5a−4.5b=3a+3b\] Subtract 3a from both sides: \[1.5a−4.5b+−3a=ou get3a+3b+−3a\] You get: \[−1.5a−4.5b=3b\] Add 4b to both sides: \[−1.5a−4.5b+4.5b=3b+4.5b\] You get: \[−1.5a=7.5b\] Divide both sides by -1.5: \[\frac{ -1.5a }{ -1.5}=\frac{ 7.5b }{ -1.5a }\]
Ugh I dont know im ending up with a mess everytime i try it
Nvm, I see what pooja is leading to. Solve for a in terms of b in the first equation, then solve for b in terms of a in the first equation. Then you'll find out the only value that a and b could be.
a=-5b Sub -5b in place of a in: \[5.5b=−2.5a+5b\] \[5.5b=−2.5−5b+5b\] \[5.5b=17.5b\] Subtract -17.5b to both sides: \[5.5b−17.5b=17.5b-17.5b\] To get: \[-12b=0\] Divide both sides boy -12 to get: \[\huge~b=0\]
Does this make sense?
I always struggle with linear equations and my SAT is coming up and I'm scared, but yeah does make sense
I took the SAT for times this year before getting a decent score, it's hard at first, but once you keep practicing you'll get it :) Khan academy is the way to go for practice! You're on the right path. To complete the problem, we had said that a=-5b We had gotten b=0 from the work previously done so : \[\huge~a=-5(0)=0\] So a=0 and b=0, what would our final answer be?
*4 times
pooja is doing well so far, I am just trying to think of a way to do this without as much arithmetic or distribution
^I was hoping there would be a shortcut of some sort because this was the SAT, you wouldn't have this much time to do this much work on the actual test
If you guys figure out a shortcut please share :S
Also a tip for the SAT, in my 4 times taking the test I have realized that the numbers are usually small when it comes to the free response math portion. This does not mean that the answer can't be big but typically it is small. This problem is a perfect example because the answer would be 0 (sorry for the giveaway) . As you can see the answer is a small number
Yes, that is true ... If there are any other tips anybody has about the SAT PLEASE PLEASE SHARE!
Also, consider looking at this https://questioncove.com/study#/updates/59f6639f7103626820a59c00 From @Vocaloid
You looked at it lol *face palm* I'll pass on more things that I can think of
pretty sure this will be on the calculator portion of the test especially with these decimals.. after distribution you can use your calculator to find a and b values
Yes @pooja195 I looked at that and @Vocaloid gave me many valuable tips which I am following now, I got the khan academy idea from her, otherwise I did not know how to start
if you re-arrange the equations so they're in the same format you get 1.5a - 4.5b = 3(a+b) -2.5a + 5.5b = 5(b-a)
@Nnesha On khan academy the question is shown as a free response
adding them together you get - a + b = b - a = 3(a+b) + 5(b-a)
OKau and the 1.5 , -2.5 etc are ignored
you don't "ignore" them, it's just that the decimals cancel out and give you b - a on the left side
anyway, if I did my math correctly I get a = 7b and you could substitute this back into the original equation and solve for b I guess? :S
using this logic I also get b = 0 and a = 0
@pooja195
I got something completely different but I am very sure I am wrong
so I just picked one of the original equations and let a = 7b and solved for b
And how did you get a=7b again
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid adding them together you get - a + b = b - a = 3(a+b) + 5(b-a) \(\color{#0cbb34}{\text{End of Quote}}\) comes from this
Don't know why that link was messing up c;
OKay will make notes :S
I took that and then solved for a in terms of b
by expanding everything and putting a and b on separate sides of the equation
ANd then the other numbers canceled out right
we were basically left with the variables
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid if you re-arrange the equations so they're in the same format you get 1.5a - 4.5b = 3(a+b) -2.5a + 5.5b = 5(b-a) \(\color{#0cbb34}{\text{End of Quote}}\) I would recommend starting from here
okay thanks
add the two equations together
and that is what makes them cancel out then we are left with - a + b = b - a = 3(a+b) + 5(b-a)
yes
then you distribute everything and solve for a in terms of b
right
I need help with one more type of problem let me repost it if you don't mind
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