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Mathematics 13 Online
zarkam21:

?

zarkam21:

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Vocaloid:

"write degrees C as a function of degrees F" implies that C should be the dependent variable and F should be independent

Vocaloid:

in other words, you are treating the degrees C values as y and degrees F as x

Vocaloid:

so you would find the linear equation between points (32,0) and (212,100) and write this in terms of C and F

zarkam21:

@pooja195

zarkam21:

@Vocaloid it would depend on each other right

Vocaloid:

I am not exactly sure what you mean by this

zarkam21:

c=fx?

Vocaloid:

your function should be in terms of C and F only

zarkam21:

c=f

Vocaloid:

good, so it would look something like that, except with a slope/intercept/etc.

Vocaloid:

if it helps, treat (32,0) and (212,100) as (x,y) points and calculate it as if everything were in x and y

Vocaloid:

then just replace x and y with F and C

zarkam21:

slope is 5/*9

Vocaloid:

good what about the y-intercept?

zarkam21:

um it could be 0 or 100

Vocaloid:

y = mx + b 0 = (5/9)(32) + b solve for b

Vocaloid:

leave it as a fraction

zarkam21:

-160/9

Vocaloid:

awesome so your final eq is C = (5/9)F - (160/9)

zarkam21:

wait so this is 3A right

zarkam21:

well 3b is 5/9

Vocaloid:

good, and 5/9 is the rate at which celsius changes per 1 degree change in fahrenheit

Vocaloid:

and the y-intercept is the temperature in degrees celcius at 0 degrees fahrenheit

Vocaloid:

I suppose you could also mention that -160/9 is approximately -17.78 degrees celcius since that's more intuitive to the average person

zarkam21:

and a is c=f right?

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid awesome so your final eq is C = (5/9)F - (160/9) \(\color{#0cbb34}{\text{End of Quote}}\)

zarkam21:

oh so that would be a?

Vocaloid:

yes

Vocaloid:

I have to go to class, I'll help you later hopefully ;_;

zarkam21:

Sounds good

zarkam21:

Good luck

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