Let f(x) = 6(2)^x−1 + 4 . The graph of f(x) is stretched vertically by a factor of 4 to form the graph of g(x) . What is the equation of g(x) ? Enter your answer in the box. g(x) = ___________
I am not 100% sure on this but I believe you would just multiply this part 6(2)^(x−1) by 4 to get 24(2)^(x-1) and leave everything else alone :S
6(2)^(x−1) x 4 ?
yes
@sillybilly123 can you double check this I am having a brain fart on this question ;_;
let me the pic
24(2)^(x-1) + 4 is my best guess
the answer ?
yes
The graph of g(x) is a transformation of the graph of f(x) = 3^x . https://static.k12.com/nextgen_media/assets/8122706-AL1_UT_A6_Pool6_NP100_267.png Enter the equation for g(x) in the box. g(x) = ___________
seems like it's up 1 unit and to the left 2 units
so you would add 1 to the entire function, and then add 2 to exponential part
1 + 2
i know it's not correct
so adding 1 to the entire function would just be sticking a +1 at the end to get f(x) = 3^x + 1 adding 2 to the exponential part would just be adding 2 to x only so f(x) = 3^(x+2) + 1 would be my best guess as the final answer
g(x) = f(x) = 3^(x+2) + 1
it's not equal to f(x) but otherwise yeah g(x) = 3^(x+2) + 1
g(x) = 3^(x+2) + 1 this one ?
yes
The graph shows the parent function f(x)=2(0.5)^x. https://static.k12.com/nextgen_media/assets/8079954-NG_AL1_SemA_06_UT_29.png Which graph represents the function g(x) = 2(0.5)^x − 1? A. https://static.k12.com/nextgen_media/assets/8079958-NG_AL1_SemA_06_UT_33.png B. https://static.k12.com/nextgen_media/assets/8079956-NG_AL1_SemA_06_UT_31.png C. https://static.k12.com/nextgen_media/assets/8079955-NG_AL1_SemA_06_UT_30.png D. https://static.k12.com/nextgen_media/assets/8079957-NG_AL1_SemA_06_UT_32.png
depends on whether the -1 is part of the exponent or not
if it's part of the exponent it's a transformation 1 to the right if it's not part of the exponent it's a transformation 1 down
\[ 2(0.5)^{x − 1}\] this?
yes
then it's to the right 1 unit
wait no
x up and - 1 down
well, we can eliminate 2 choices based on the shape of the graph alone
b and a
so A and D are the wrong shape so we can eliminate these
which graph is the original graph translated 1 unit down? b or c?
c
awesome good work ^_^
https://static.k12.com/nextgen_media/assets/8079943-NG_AL1_SemA_06_UT_34.png The linear function in the graph shows the value, in dollars, of an investment in years after 2012. The exponential function in the table represents the balance of a savings account, in dollars, over time in years after 2012. How does the y-intercept of the exponential function compare to the y-intercept of the linear function? Drag the correct answer to the box to complete the statement. approximately 130 more than approximately 130 less than approximately 30 more than approximately 30 less than The y-intercept of the exponential function is ____________ the y-intercept of the linear function.
i'll send pic
so each consecutive year the balance is being multiplied by 3 to go backwards we do the opposite, by dividing by 3
if the year 2 value is 180, we can get the year 1 value by dividing the year 2 balance by 3
so 180/3 = ?
60
good, and to get the year 0 we divide that by 3 so 60/3 = ?
20
good so the exponential y-intercept is 20 what about the y-intercept of the graph?
the y - intercept is 30 less
just look at the graph for now (not the exponential part/calculations.etc) what is the value of the graph when x = 0?
the answer for this is 0
my computer was acting up again
put your finger on the graph when x = 0 then go up until you touch the graph
10
|dw:1510872726787:dw|
|dw:1510872733060:dw|
|dw:1510872746013:dw|
what is the value of the graph at this point?
150
|dw:1510872774741:dw|
good, 150
so the difference between the linear and exponential y-intercepts is: 150 - 20 = 130
so therefore is 130 more or less so it's more
and since we've solved it it's more
we need to pay attention to how the question is phrased
The y-intercept of the exponential function is ____________ the y-intercept of the linear function. since the exponential y-intercept was less than the linear intercept, "less than" needs to be in the blank
oh i had that first but ok
What is the average rate of change of the function on the interval from x = 1 to x = 2? f(x) = 10(5.5)^x Enter your answer, as a decimal, in the box. ___________
average rate of change formula
"5.5" was replaced by "(55/10)".
|dw:1510873068901:dw|
start by calculating f(2) and f(1) using f(x) = 10(5.5)^x
f(2) - f(1) right ?
yes, but you must calculate f(2) and f(1) separately using the equation, then subtract the results
f(2) means let x = 2 and calculate f(x)
f(2)=(4)^x-1 right ?
or no
wait
my apology
generally you do not carry over information from other problems into new problems
in this problem, f(x) = 10(5.5)^x
f(2) = 10(5. 5)^x
right ?
you're on the right track, but you also need to replace the other x with 2
f(2) = 10(5. 5)^2 = ?
f = 605/4 = 151.250
remember that the 2 exponent only gets applied to the 5.5
calculate 5.5^2 and then multiply the result by 10
112 ——— = 30.25000 the answer for 5. 5^2 22
you can just use a calculator for these ^_^
121x^10 —————— 4
is it correct ?
you can just type calc into google to give you a calculator
ok type what into the calculator again ?
10(5. 5)^2 = this
302.5
good now do the same thing with 10(5. 5)^1
55
good now those are our f(2) and f(1) values now we plug these into the average rate of change eqn
[f(2) - f(1)]/(2-1) = (302.5 - 55)/(2-1) = ?
247.5
good that's our answer ^^ got to go now, have a great night ~
wait wait
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