The number of students enrolled in a new course as a function of time can be represented by the function. f(x) = (4)^x − 1 What is the average increase in the number of students enrolled per hour between hours 2 and 4? Enter your answer in the box. _______________
@Vocaloid
First you'll plug 2 and 4 for x to find f(x) and then you'll find the rate of change
f(2) = 4^2 - 1 Can you simplify 4^2 - 1?
it is 15
Correct so when x = 2, f(x) = 15 Now for x = 4 f(4) = 4^4 - 1 Could you simplify that
255
Correct Now the average is \(\bf\dfrac{f(4)-f(2)}{4-2}=\dfrac{255-15}{4-2}=?\)
120
So 120 is your answer
ok thx for that and could you help me with other questions if you have the time if it's ok with u?
Sure
ok hold on
Drag and drop the answer into the box to identify each function as linear, exponential, or neither. linear exponential neither
i'll send the pic
You'd have to find the rate of change Know how to?
well i think i have it
the first is exponential the second is linear correct me
I think you have it backwards lol For the first one it's a constant rate of 1.5 which is \(\bf linear\) And then for the second one, it seems like it's 2^x, so 2^0 = 1, 2^3 = 8, 2^6 = 64 which makes it \(\bf exponential\)
oh so i had but it's backwards
Yep
i'll send the pic
Function f is an exponential function. By what factor does the output value increase as each input value increases by 1? Enter your answer in the box. ____________
Any idea?
no
do you ?
I know the answer but am not sure how to explain it
I basically kept multiplying by 2 each time and got the same thing
Idk why there's an image
ok
so what is it ?
mehek ?
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