Express answer in exact form. Show all work for full credit. A segment of a circle has a 120 arc and a chord of 8sqrt 3in. Find the area of the segment. Can someone please help me with this? I'm literally about to have a mental breakdown.
@Vocaloid
She can help explain everything to you
Thank you...
Any chance you could screenshot your question? It might make it a little easier for us to understand.
|dw:1512164581740:dw|
the area of the shaded part is the area of the entire sector - the area of the triangular part
to find the area of the triangular part we will bisect the chord to produce two 30-60-90 triangles |dw:1512164675309:dw|
given that the entire chord is \[8\sqrt{3}\] the half chord is \[4\sqrt{3}\]
|dw:1512164752608:dw|
using our 30-6-90 triangle ratios we get|dw:1512164782478:dw|
now we know: the height of each triangle, the base of each triangle, and the radius of the circle. these three pieces are enough to calculate the area using our original equation area shaded = area sector - area of triangles for a sector, the area is (angle of sector/360)*pi*r^2 area of each triangle is (1/2)(bh) r = 8 angle of sector = 120 b = 4sqrt(3) h = 4 let me know if you had any trouble understanding anything
Thank you so much... You did make it easier to understand.. I had my answer right, my teacher just wanted it in a different format I guess. :)
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