Question

http://prntscr.com/hhzmg0
Can you help me with B, C, and D?

Answer 1

@Angle

Answer 2

uuhm...

Answer 3

@UltraInstinct Welcome to QuestionCove! :)

Please wait while I read over your question ^_^

Answer 4

thanks for the welcome!
and, okay then :)

Answer 5

Ok!

so are you familiar with the formula to find slope?

\(\large slope = \huge \frac{rise}{run} = \huge\frac{y_2 - y_1}{x_2 - x_1}\)

given the points \((x_1 ,~y_1)\) and \((x_2,~y_2)\)

Answer 6

yeh, I know the slope formula

Answer 7

so the two points they give us for Line r
are
(m, n) and (j, k)

thinking of these two points like
\((x_1, ~y_1)\) and \((x_2,~y_2)\)

can you plug that into the slope formula?
what would you get?

Answer 8

I thought it was (x1, x2) and (y1, y2)?
If it's how you said, then it'd be (m, n) and (j, k) right?
somethin like that

Answer 9

I'll draw a picture to show you more clearly, give me a sec ^_^

Answer 10

okie~

Answer 11

So when we are using coordinate points, they are in the form: (x, y)
where x = how far left or right the point is
and y = how far up or down the point is

Answer 12

So when we say
\((x_1, ~y_1)\) and \((x_2,~y_2)\)
we are saying there are two points
(x, y) and (x, y)
but to say that they are different, we put numbers next to them
\(x_1\) is the x value of the "first" point
\(x_2\) is the x value of the "second" point

so these two things in parenthesis are different points with different x and y values each

Answer 13

mm, I think I got it now

Answer 14

Thanks~ :)

Answer 15

Awesome :)

the slope for Line s uses the same idea
do you need help with that one as well?

Answer 16

I think I can do it. But now I gotta figure out how to make an expression for it while working... is D the same also?

Answer 17

D is a little different

but it uses the idea that
y = how much up or down

for the first P', the y value of P' = (n + e)
and we want to move that 3 units "down"
so the y value for P'' = (n + e - 3)

then all you have to do is put it in the (x, y) form

Answer 18

hm, okay then, Thank you again~ :D

Answer 19

No problem :)

if you need any more help, feel free to get my attention with the tag @Angle
good luck!

Answer 20

okay!