Question

http://prntscr.com/hime61
Show work

Answer 1

@dude

Answer 2

@Angle

Answer 3

distribute first?

Answer 4

exponents first

Answer 5

?

Answer 6

no its distribute

Answer 7

(4 x^4 y^3)^2 = 16 x^8 y^6

Answer 8

its distribute

Answer 9

3(4 x^4 y^3)^2 = 3 ( 16 x^8 y^6 ) = 48 x^8 y^6

Answer 10

are you even listening to me

Answer 11

then show me what you mean

Answer 12

distribute first

Answer 13

show me what you mean

Answer 14

\[\frac{ 3(4x^{4}y ^{3})^{2} }{ (5x ^{2}y ^{6})^{3} }\]

Answer 15

\[\frac{ 3(4^{2}x ^{8}y ^{6}) }{ (5^{3}x ^{6}y ^{18}) }\]

Answer 16

^distributed

Answer 17

perfect

Answer 18

then simplified with exponents

Answer 19

\[\frac{ 3(16x ^{8}y ^{6}) }{ 125x ^{6}y ^{18} }\]

Answer 20

you cant simplify 3 and 125

Answer 21

indeed you can't

Answer 22

is that all done now?

Answer 23

variables can reduce

Answer 24

numerator 3*16 can be simplified

Answer 25

48x^8y^6/125x^6y^18

Answer 26

x^8 / x^6 = x^2

Answer 27

?

Answer 28

\(\huge \frac{x^8}{x^6} = \frac{x*x*x*x*x*x*x*x}{x*x*x*x*x*x} = \large x*x = x^2\)

Answer 29

-18 for both exponents in the numerator?

Answer 30

that isnt the same way my teacher showed me how to do it
her steps were
Distribute
SImplify
find GCF
Subtract denominator exponent from numerator exponents
DOne

Answer 31

yes, I am at the "Subtract denominator exponent from numerator exponents" step
for the x variables
x^8 minus the x^6 from the denominator gives you x^2

Answer 32

i meant the y^18 - x^8 and y^6

Answer 33

x^8 - 18
y^6-18

Answer 34

x^-10
y^-12

Answer 35

but the practice problem both had x^18 and y^18

Answer 36

x can only subtract x
y can only subtract y

Answer 37

the 18 from the y^18 only subtracts from the y^6
it does not touch the x

Answer 38

so

Answer 39

\[\frac{ 48x ^{2}y ^{-12} }{ 125 }\]

Answer 40

?

Answer 41

awesome

Answer 42

done?

Answer 43

\(\huge \frac{48x^2}{125y^{12}}\)

you can write it like this if you want
but yes
done

Answer 44

yay i can math