Can someone please look over my work?? My teacher said I don't need the decimals, so how should it be drawn?
Express answer in exact form. Show all work for full credit.
A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle.
(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4s^2sqrt 3)
My answer-
The angle subtended by one segment is 360/6 = 60 degrees.
The area of the triangle is 1/2 * 3 * 3 x sin 60
=9/2 x √3/2
= 9/4 x √3
The area of the sector of the circle is 1/6 (π x 3²)
= 9/6π
So the area of segment is sector minus triangle
= 9/6 π - 9/4√3
= 4.71 - 3.9
= 0.81

Question

Can someone please look over my work?? My teacher said I don't need the decimals, so how should it be drawn?
Express answer in exact form. Show all work for full credit.
A regular hexagon with sides of 3" is inscribed in a circle. Find the area of a segment formed by a side of the hexagon and the circle. 
(Hint: remember Corollary 1--the area of an equilateral triangle is 1/4s^2sqrt 3)
My answer-
The angle subtended by one segment is 360/6 = 60 degrees.
The area of the triangle is 1/2 * 3 * 3 x sin 60
=9/2 x √3/2
= 9/4 x √3
The area of the sector of the circle is 1/6 (π x 3²)
= 9/6π
So the area of segment is sector minus triangle
= 9/6 π - 9/4√3
= 4.71 - 3.9
= 0.81

sammirosesharp · Answer

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