Question

Help please

Answer 1

going from standard to vertex form is the most difficult so let's start with that

y = x^2 - 2x - 3

first we add 3 to both sides to isolate the x^2 and x terms

y + 3 = x^2 - 2x

now, we need to add/subtract some number (c) to make the right side a perfect square

Answer 2

if a is the coefficient on the x^2 term (1) and b is the coefficient on the x term (-2)

we can use the formula c = (-b/2a)^2 to find that value of c

Answer 3

b = -2
a = 1

c = (-b/2a)^2 = ?

Answer 4

4

Answer 5

check your calculations again ^^ the denominator should be 2a not a

Answer 6

-2/2

Answer 7

-1

Answer 8

1?

Answer 9

good ^^ so we add 1 to each side to get

y + 3 + 1 = x^2 - 2x + 1

factor the right hand side

Answer 10

would it be y=(x-1)^2-4

Answer 11

good, but judging by their format they want you to write it as y + k = (x-h)^2 so it would be

y + 4 = (x-1)^2

Answer 12

and this would be vertex form for the first one right?

Answer 13

yes

Answer 14

to go from standard to intercept, simply factor y = x^2 - 2x - 3

Answer 15

x-3,,, x+1?

Answer 16

good so y = (x-3)(x+1) = intercept form

and that's it for row 1

Answer 17

for row 2, start with vertex form and convert to standard by expanding y - 5 = -2(x+1)^2 using foil

Answer 18

would it be \[y=-2x^2-4x+3\]

Answer 19

good

now to go from that to vertex form, simply factor it

Answer 20

hm it looks like it doesn't factor evenly let me check my calculations again

Answer 21

Yes that's what i concluded as well

Answer 22

we could use the quadratic formula

Answer 23

OKay

Answer 24

Here's a tip, use socratic. lmao. It's an app, i don't think they have it for android but they do have it for IPhones. You just scan the equation and it shows you how to do it along with giving you the answer in case you need to check. It works for science and history too.

Answer 25

I actually like knowing how to solve it by myself :(

Answer 26

Ah, well good luck. :)

Answer 27

ngl I kinda forgot what to do from here to turn it into an eqn

Answer 28

(x + 3)(2x − 1) = 0

Answer 29

@AngeI

Answer 30

I don't think that's quite right ^^

Answer 31

OH okay :/

Answer 32

this is what wolfram alpha gives me but bleurgh

Answer 33

we can go back to it i guess

Answer 34

Yeah that's what I got but i don't think that isright
i got the same on mathway

Answer 35

anyhoo, for row 3, to go from vertex to standard you just expand (x+2)(x-3) using foil

Answer 36

\[y=(x-\frac{ 1 }{ 2 })^2-\frac{ 25 }{ 4 }\]

Answer 37

oh uh are you still working on that row 2 equation?

Answer 38

no this is the vertex form for the third row

Answer 39

oh, well it's easier to go from intercept to standard first ^_^ so just expand (x+2)(x-3)

Answer 40

I'm not getting it quite right

Answer 41

foil, first outer inner last

(x+2)(x-3) = x^2 - 3x + 2x - 6 = x^2 -x - 6

*** sorry, typo

Answer 42

then to go from standard (x^2 -x - 6) to vertex we just need to use the method we did at the beginning (completing the square)

y = x^2 - x - 6

y + 6 = x^2 - x

using the same method we did earlier, find c = (b/2a)^2

Answer 43

@Vocaloid dont we have latex witch would make this easier to read?