Question

Helps

Answer 1

Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
A two column proof of the theorem is shown, but a justification is missing.

Statement Justification
The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) Midpoint Formula
Length of segment DE is Square root of 5 and length of segment AC is 2 multiplied by the square root of 5. Distance Formula
Segment DE is half the length of segment AC.
Slope of segment DE is −2 and slope of segment AC is −2. Slope Formula
Segment DE is parallel to segment AC. Slopes of parallel lines are equal.

Answer 2

Which is the missing justification?
Additive Identity
By Construction
Midsegment Theorem
Substitution Property of Equality

Answer 3

@Angle

Answer 4

dang
this is actually a weird questino

Answer 5

Theres ten questions if you are up to it ¯\_(ツ)_/¯ but if you want a differant question I can give another to you @Angle :D

Answer 6

Length of segment DE is Square root of 5 and length of segment AC is 2 multiplied by the square root of 5. Distance Formula

this gives us
\(DE = \sqrt{5}\)
\(AC = 2 \sqrt{5} \)
\(\rightarrow \sqrt{5} = \large \frac{AC}{2}\)

so
\(DE = \large \frac{AC}{2}\)
which translates to "Segment DE is half the length of segment AC."

so I guess this might be considered a roundabout way of saying "substitution property of equality" because we are saying sqrt(5) = sqrt(5) then turning that into DE and AC/2

Answer 7

Sub property alright got it.