http://prntscr.com/hm371o Compute the perimeter of the rectangle using the distance formula. (round to the nearest integer) A) 33 B) 34 C) 38 D) 45
I'm only sometimes good at math, depending on how much calculus+trigonometry I've had to do over the course of the day. At this current time my mind is fried from math and I'm unable to help @Vocaloid
or @Angle Shes online and will probably be able to help as well
@Angle
Okie thanks
Do you know the distance formula? if you don't, I can start from there
Not really
that's ok, it gets a bit difficult to memorize :P do you know the Pythagorean Theorem?
Somewhat
Names are hard to remember
\(a^2 + b^2 = c^2\) you've seen this before? ^
where a, b, and c are the lengths of the triangle |dw:1513014183134:dw|
Yes I have
For example, if a = 3 b = 4 then a^2 + b^2 = (3)^2 + (4)^2 = 9 + 16 = 25 so c^2 = 25 which means that c = 5
25 or 2.5?
9 + 16 = 25 then the \(\sqrt{25} = 5\) so c = 5 in that case
Ohhhhh
So in general: \(a^2 + b^2 = c^2\) if you square root both sides then you can get \(c = \sqrt{a^2 + b^2}\) do you see that?
Yes
awesome :) then the next idea, is to look at your rectangle like this: |dw:1513014583413:dw|
Wow
so using the \(~~~c = \sqrt{a^2 + b^2}~~~\) formula, we can find the length of one of the sides of the rectangle
First we need to find what (a) and (b) are by looking at (a) this way, how long do you think (a) is? |dw:1513014728208:dw|
As in length or height??
We're looking at the length right now :) try to find the length of (a)
13?
perfect! :D
then we try to find the height (b) would you like for me to draw in the lines for that too, or do you want to try this step yourself? :)
Probs better if you draw it out. I'm terrible at this.
|dw:1513015033297:dw|
b is 13?
so what do you think is the height (b)?
13
awesome :) then we use the Pythagorean Formula: \(c = \sqrt{a^2 + b^2}\) with a = 13 and b = 13 so \(c = \sqrt{13^2 + 13^2}\) c = ?
i walked into difficult looking math lol
XD
haha I'm just taking it step by step honestly, if you just plug it into the distance formula, it would be faster; but I feel like you would understand it better if we think of this problem with the pythagorean theorem :P
Okay so where did we leave off?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Angle then we use the Pythagorean Formula: \(c = \sqrt{a^2 + b^2}\) with a = 13 and b = 13 so \(c = \sqrt{13^2 + 13^2}\) c = ? \(\color{#0cbb34}{\text{End of Quote}}\)
338?
close :) the square root of that ^_^
Square root of 338?
yup
yeah, I'm not sure what form your teacher wants your answer, so I guess we can just remember that number for later :)
the next step is |dw:1513015927519:dw|
These are the answer options Compute the perimeter of the rectangle using the distance formula. (round to the nearest integer) A) 33 B) 34 C) 38 D) 45
Ok, that's fine :) we'll get there eventually
Okie
|dw:1513015997412:dw|
In height? Width? Length?
a = length = 3 b = height = 3 so \(c = \sqrt{3^2 + 3^2}\) c = ?
3
hmm?
If we're looking for the square root of 9
Wait, wrong. Lemme do that again
careful! \(c = \sqrt{3^2 + 3^2} = \sqrt{9 + 9}\) yeah
Yup! That's right then Perimeter of a rectangle = 2*(width) + 2*(height) = 2*(18.38...) + 2*(4.424)
So then what answer would that be in exact form?
nope because your question asks for: "round to the nearest integer"
??
what did you get for the exact answer? :) we can work from there
I don't understand. It can't be decimals. The answer options aren't decimals :/
Its just these A) 33 B) 34 C) 38 D) 45
yeah what did you get for 2*(18.384) + 2*(4.424) ?
Huh?
we get that number then the closest number to that number is your answer
How do we do that?
2 times 18.384 = ?
then 2 times 4.424 = ?
then add those two numbers
then the nearest whole number to that is your answer
1st one is 36.768
2nd is 8.848
Both added together is 45.616
So that would be D?
She had to run, so I'm answering for her, that is indeed correct.
Okie, thanks
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