Question

number 2
how do i do part b

for part a i got l(x,y) = 1

Answer 1

@sillybilly123

Answer 2

in polar, that is \(\lim\limits_{r \to 0} \cos r \), yes?

Answer 3

yes

Answer 4

yep, for part A

\(\nabla (\cos (x^2 + y^2) - z )_{0} = <0,0,1>\)

Answer 5

or

\(<0,0,-1>\)

Answer 6

okay so then

Answer 7

i think you have done part B. job finished.

Answer 8

wait what im lost was that part b what u did?

Answer 9

what do you think Part B is and what do you think the answer to Part B is?

Answer 10

every derivative is a limit. if you cannot establish a limit at a point, then ...

Answer 11

well ik its a limit

Answer 12

i think you have answered these questions. you have established that the limit is \(z(0) = 1\). and that the normal vector is \(<0,0,-1>\)

that is job done

Answer 13

hmm

Answer 14

you doubt !!

Answer 15

cool!!

Answer 16

no im not doubting lol im just wondering how is that the answer

Answer 17

werent we suppose to use some limit?

Answer 18

we used a limit for Part B, having switched Cartesian to Polar so we had: \(\lim\limits_{r \to 0} r = 0\)

Answer 19

oh okay so then

Answer 20

pretty sure that's it all

Answer 21

i can set you some questions

Answer 22

or not

Answer 23

ok

Answer 24

are you learning physics or math?

Answer 25

math

Answer 26

ouch. you won't really get this stuff unless you do a physical science. unless you have a math brain, in which case you will !!

Answer 27

lol yeh.. ive never taken physics

Answer 28

it's ALL physics. i'm afraid :( but you math bods make sure it works !

Answer 29

yah lol

Answer 30

😁

Answer 31

she uploaded the solution for this problem barely...
idk how she got 0

Answer 32

dodgy answers :) in both cases

Answer 33

dang

Answer 34

Nah!!

Answer 35

Mmmmm. Brutal stuff :( Not sure I would agree with most of that

if you need another steer, do tag @Vocaloid , the Mother Superior

i will be only to happy to addd my inept input :))