Question

http://prntscr.com/hpssco

Answer 1

@dude

Answer 2

vertical translation?

Answer 3

Yes, but thats not the only transformation

Answer 4

horizontal translation?

Answer 5

No

Answer 6

compression?

Answer 7

Does it look compressed?

Answer 8

no

Answer 9

Then no

Answer 10

the y intercept went from y = 1 to y = 2

Answer 11

the x went from x=0 to x=-3

Answer 12

Right

Answer 13

How would that be reflected in a graph?

Answer 14

dialation

Answer 15

?

Answer 16

Yes

Answer 17

Also, note by "x" you mean horizontal asymptote?

Answer 18

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Pixel
the x went from x=0 to x=-3
\(\color{#0cbb34}{\text{End of Quote}}\)

Answer 19

yes

Answer 20

the one it never touches

Answer 21

RIght

Answer 22

So what would be the equation of the graph for now?

Answer 23

g(x)=5^x-3

Answer 24

im not sure on the dialation yet

Answer 25

\[g(x)=5^x-3?\\
or\\
5^{x-3}?\]

Answer 26

first one

Answer 27

Yes, thats right

Answer 28

Can you use graphing calculators for this question?

Answer 29

it is a written test but yes

Answer 30

Do you want to do this algebraically or graphically?

Answer 31

well i need the equation

Answer 32

and there isnt room for a graph

Answer 33

Well I asking you which one do you prefer, I can do either but which would you feel more comfortable with?

Answer 34

idk what graphically so algebraically

Answer 35

Alright, the equation of an exponential equation is
\[y=a*(b)^{x-c}+d\]
We have:
\[y=a*(5)^{x-0}-3\]

Answer 36

To solve for a, we can use any point in the graph given to us

Answer 37

(Pick a point)

Answer 38

(0,2)

Answer 39

A = -1

Answer 40

Accidentally deleted my comment, AGH
But no

Answer 41

e.e

Answer 42

\[2=a*(5)^{0}-3\\
a*(5)^0-3=2~\color{red}{REMEMBER:~a~and~1~are~being~multiplied~so~in~order~\\to~get~rid~of~it~you~divide~}\\
1a-3=2\\
Divide~by~1~on~both~sides\\
a-3=2\\
a=5\]

Answer 43

that doesnt work

Answer 44

What do you mean?

Answer 45

Nvm i had my graph zoomed out too far

Answer 46

So your equation is
\[g(x)=5\cdot(5)^x-3\]