Question

help please

Answer 1

where (h,k) is the vertex

compare y = a(x-h)^2 + k
with y = 2(x-1)^2 + 3

what are h and k?

Answer 2

2 and 3

Answer 3

almost

Answer 4

-h = -1

h = 1

making the vertex (1,3)

now plot this point onto the graph

Answer 5

okay so for part I

Answer 6

it would be

Answer 7

(1,3)

Answer 8

then for part II

Answer 9

just plot 1,3 right

Answer 10

part II is asking to find the y intercepts

Answer 11

the graph is still part of part I

Answer 12

ohhh sorry for part one the graphing part i would graph 1,3 right

Answer 13

yes

Answer 14

okay now for part II

Answer 15

plug 0 for x into the equation y = 2(x-1)^2 + 3 and find y.

Answer 16

y=2(0-1)^2+3
y=0-4+3
y=-1

Answer 17

(0-1)^2 = ?

Answer 18

i thought i had to distribute the 2 first

Answer 19

PEMDAS

parentheses
exponents
mult/divide
add/subtract

exponents come first

Answer 20

y=5

Answer 21

good, so (0,5) is the only y-intercept

add that to the graph

Answer 22

okay

Answer 23

okay part III

Answer 24

to find any x intercepts substitute 0 for y

0 = 2(x-1)^2 + 3

^ what solutions, if any, does this have?

Answer 25

2

Answer 26

wait do I solve using the quadratic formula

Answer 27

think about it algebraically

-3 = 2(x-1)^2

when you take the square root of both sides you get 3i on the left side

meaning this has no (real) solutions

so no x-intercepts

Answer 28

for part IV simply finish the parabola with the two points you have already plotted

Answer 29

would it be upward or downward

Answer 30

y = 2(x-1)^2 + 3

the coefficient of x^2 is positive making the graph upward

Answer 31

okay

Answer 32

perfect thanks