Hwlp
@sillybilly123 can you take a look at this when you get a chance
True
|dw:1515464547984:dw|
there's a pattern in there try x= 1 1 + 1 - 11 - 9 + 18 = 0 then divide it out Voca - short of finding a crystal ball or a magic lamp, do you see a way round this?!?!
zarky: start dividing that by \(x-1\) and see what happens
so divide 1 + 1 - 11 - 9 + 18 = 0 by x-1
divide the original quartic by (x-1) ????
I got \[x^3+2x^2-9x-18\]
\(\huge \checkmark\)
So it would be false?
that's just one root! you gotta solve again
oh okay
so try 1, 2, 3, .... and -1, -2, -3,......
like x-1,x-2,x-3 right?
i don't know what you are learning, so maybe just plotting this is an easy way round it. you know...proving that if \(x >5\) then it just keeps increasing. that requires a certaain kind of knowledge but maybe you are just learning how to find roots. so if you could show that \(f(5)>0\) and that \(f'(5) > 0\) you might be sorted.
not a mind reader, but what you say sounds sensible :)
x-2:
x-3
x-(-1)
x-(-2)
x-(-3)
sure try this: \((x+3)(x-3)(x+1)(x-1)\)
so divide the equation given by (x+3)(x−3)(x+1)(x−1)
the equation is the product of those terms
but I don't see how that is a reasonable answer to the question asked. if you could step back and show that \(f(x) >0\) for all \(x > 5\) ..... that's smarter no idea right now where to start that one though, without jumping upon Calculus. And that is off the menu
but yes, factoring the thing shows ALL the zeroes so you can see that the one furthest along the number line is actually x=3 which proves the point they want you to make.
zarky: you reasonably happy with that ?!?!
so true?
tops
true or false
so @Vocaloid this would be true right, I don't quite understand.
I guess it's true judging by what math has been done so far ;;
Okay thanks, I sometimes don't understand him ^-^
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