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Mathematics 7 Online
zarkam21:

Hwlp

zarkam21:

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Vocaloid:

@sillybilly123 can you take a look at this when you get a chance

zarkam21:

True

sillybilly123:

|dw:1515464547984:dw|

sillybilly123:

there's a pattern in there try x= 1 1 + 1 - 11 - 9 + 18 = 0 then divide it out Voca - short of finding a crystal ball or a magic lamp, do you see a way round this?!?!

sillybilly123:

zarky: start dividing that by \(x-1\) and see what happens

zarkam21:

so divide 1 + 1 - 11 - 9 + 18 = 0 by x-1

sillybilly123:

divide the original quartic by (x-1) ????

zarkam21:

I got \[x^3+2x^2-9x-18\]

sillybilly123:

\(\huge \checkmark\)

zarkam21:

So it would be false?

sillybilly123:

that's just one root! you gotta solve again

zarkam21:

oh okay

sillybilly123:

so try 1, 2, 3, .... and -1, -2, -3,......

zarkam21:

like x-1,x-2,x-3 right?

sillybilly123:

i don't know what you are learning, so maybe just plotting this is an easy way round it. you know...proving that if \(x >5\) then it just keeps increasing. that requires a certaain kind of knowledge but maybe you are just learning how to find roots. so if you could show that \(f(5)>0\) and that \(f'(5) > 0\) you might be sorted.

sillybilly123:

not a mind reader, but what you say sounds sensible :)

zarkam21:

x-2:

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zarkam21:

x-3

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zarkam21:

x-(-1)

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zarkam21:

x-(-2)

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zarkam21:

x-(-3)

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sillybilly123:

sure try this: \((x+3)(x-3)(x+1)(x-1)\)

zarkam21:

so divide the equation given by (x+3)(x−3)(x+1)(x−1)

sillybilly123:

the equation is the product of those terms

sillybilly123:

but I don't see how that is a reasonable answer to the question asked. if you could step back and show that \(f(x) >0\) for all \(x > 5\) ..... that's smarter no idea right now where to start that one though, without jumping upon Calculus. And that is off the menu

sillybilly123:

but yes, factoring the thing shows ALL the zeroes so you can see that the one furthest along the number line is actually x=3 which proves the point they want you to make.

sillybilly123:

zarky: you reasonably happy with that ?!?!

zarkam21:

so true?

sillybilly123:

tops

zarkam21:

true or false

zarkam21:

so @Vocaloid this would be true right, I don't quite understand.

Vocaloid:

I guess it's true judging by what math has been done so far ;;

zarkam21:

Okay thanks, I sometimes don't understand him ^-^

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