Write a proof to show that a rectangle has congruent diagonals. Be sure to create and name the appropriate geometric figures. This figure does not need to be submitted.
|dw:1515521694046:dw|
|dw:1515521749583:dw|
BD^2 = BC^2 + DC^2 (pythagorean theorem, where DC is the diagonal)
|dw:1515521790406:dw|
AC^2 = DC^2 + AD^2 (also the pythagorean theorem)
BD^2 = BC^2 + DC^2 AC^2 = DC^2 + AD^2 we concluded earlier that BC and AD are congruent (because they're opposite sides of a rectangle) which means BD^2 and AC^2 are both equal to BC^2 + DC^2 since the side lengths of a rectangle are always positive, we can take the square root of both sides and conclude that BD = AC = sqrt(BC^2 + DC^2) ^ proving the diagonals are equal done
*** also I need to mention that angle C and angle A are 90 degree angles (since this is a rectangle) making both triangles right triangles, which is why we can use the pythagorean theorem in the first place
so much lol ok
Join our real-time social learning platform and learn together with your friends!